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Derivative of (x^2 + 4)(x^2 - 1)

Step by step, with the reason for every step · Product and quotient rules · Calculus

Step by step

The question

Question: find the derivative of f(x) = (x² + 4)(x² − 1).

f(x) = (x2 + 4)(x2 − 1)

1 Name u and v

Call the first bracket u: x² + 4.

u = x2 + 4

Call the second bracket v: x² − 1.

v = x2 − 1

2 Find u′ and v′

The power rule on u gives u′ = 2x.

u′ = 2x

On v it gives v′ = 2x.

v′ = 2x

3 Use the rule

The product rule: the derivative of u times v is u′ v plus u v′.

(uv)′ = u′v + uv′

Put them in.

f′(x) = (2x)(x2 − 1) + (x2 + 4)(2x)

Careful!

Not u′ times v′!

Each part needs the other bracket.

Careful: not u′ × v′ = 4 x² ✗

4 Open the brackets

What is in front of a bracket multiplies every part inside.

= 2x3 − 2x + 2x3 + 8x

Terms are the parts between the + and − signs.

Like terms are the same kind: same letters, same powers.

All the x terms go together.

Plain numbers go together.

So f′(x) = 4 x³ + 6x.

= 4x3 + 6x

5 Check

Let's check another way: multiply the brackets out first.

f(x) is x⁴ + 3 x² − 4.

f(x) = x4 + 3x2 − 4

The power rule on that gives 4 x³ + 6x.

The same!

Right!

f′(x) = 4x3 + 6x

Let's look back.

First: name u and v.

Then: find u′ and v′.

Then: use the rule.

Then: open the brackets.

Last: check.

Answer
= 4x3 + 6x

Your turn

Try this one yourself, then check:

Find the derivative of f(x) = (x2 + 2)(x2 − 2)
Show the answer
f′(x) = 4x3

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