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Diagonal of a box 3 cm by 4 cm by 5 cm

Step by step, with the reason for every step · Pythagoras in 3D · Geometry

Step by step

The question

Question: find the diagonal of a box 3 cm by 4 cm by 5 cm.

box 3 cm by 4 cm by 5 cm

The diagonal goes from a bottom corner to the top corner on the other side, right through the box.

1 Floor diagonal

First the floor.

Its diagonal d makes a right triangle with the sides 3 and 4.

Pythagoras: d squared is 3 squared plus 4 squared.

3 times 3 is 9.

4 times 4 is 16.

Together 25.

d2 = 32 + 42 = 9 + 16 = 25
a² + b² = c²

5 times 5 is 25.

So d is 5.

d = √25 = 5

Careful!

We cannot just add the sides.

A diagonal is a short cut: Pythagoras, twice.

Careful: not 3 + 4 + 5 = 12 ✗

2 Diagonal of the box

Now a new right triangle stands up: the floor diagonal d, the height 5, and the diagonal D of the box.

Pythagoras again: D squared is d squared plus 5 squared.

d squared is 25.

5 times 5 is 25.

Together 50.

D2 = d2 + 52 = 25 + 25 = 50

50 is not a square number.

A calculator gives 7.071, and so on.

D = √50 = 7.071…

To the nearest tenth, D is about 7.1 cm.

D ≈ 7.1 cm

3 Check

Let's check: the two steps are the same as l squared plus w squared plus h squared.

9 plus 16 plus 25 is 50, the same D squared.

So the answer is right!

3² + 4² + 5² = 9 + 16 + 25 = 50

Let's look back.

First: floor diagonal.

Then: diagonal of the box.

Last: check.

Answer
D ≈ 7.1 cm

Your turn

Try this one yourself, then check:

box 8 cm by 6 cm by 3 cm
Show the answer
D ≈ 10.4 cm

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