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Longest pole that fits in a box 4 by 4 by 7

Step by step, with the reason for every step · Pythagoras in 3D · Geometry

Step by step

The question

Question: what is the longest pole that fits in a box 4 by 4 by 7?

box 4 by 4 by 7

The longest thing that fits goes from a bottom corner to the top corner on the other side: the diagonal through the box.

1 Floor diagonal

First the floor.

Its diagonal d makes a right triangle with the sides 4 and 4.

Pythagoras: d squared is 4 squared plus 4 squared.

4 times 4 is 16.

4 times 4 is 16.

Together 32.

d2 = 42 + 42 = 16 + 16 = 32
a² + b² = c²

32 is not a square number.

We do not need d itself: the next step uses d squared.

keep d² = 32

Careful!

We cannot just add the sides.

A diagonal is a short cut: Pythagoras, twice.

Careful: not 4 + 4 + 7 = 15 ✗

2 Diagonal of the box

Now a new right triangle stands up: the floor diagonal d, the height 7, and the diagonal D of the box.

Pythagoras again: D squared is d squared plus 7 squared.

d squared is 32.

7 times 7 is 49.

Together 81.

D2 = d2 + 72 = 32 + 49 = 81

9 times 9 is 81.

So D = 9.

D = √81 = 9

3 Check

Let's check: the two steps are the same as l squared plus w squared plus h squared.

16 plus 16 plus 49 is 81, the same D squared.

So the answer is right!

4² + 4² + 7² = 16 + 16 + 49 = 81

Let's look back.

First: floor diagonal.

Then: diagonal of the box.

Last: check.

Answer
D = √81 = 9

Your turn

Try this one yourself, then check:

box 2 by 3 by 6
Show the answer
D = 7

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