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Distance (1, 2, 3) (2, 4, 6)

Step by step, with the reason for every step · Points and distance in space · Calculus 3

Step by step

The question

Question: find the distance between (1, 2, 3) and (2, 4, 6).

(1, 2, 3) and (2, 4, 6)

1 Plot the points

Draw the three axes: x toward us, y right, z up.

Point A: (1, 2, 3).

Point B: (2, 4, 6).

The distance is the length of this straight segment.

2 The differences

Along x: x goes from 1 to 2.

2 minus 1 is 1.

2 − 1 = 1

Along y: y goes from 2 to 4.

4 minus 2 is 2.

4 − 2 = 2

Up z: z goes from 3 to 6.

6 minus 3 is 3.

6 − 3 = 3

3 Square and add

On the flat, the x and y moves make a right triangle.

Its long side is this green line.

The green line and the move up z make a second right triangle.

Its long side is AB.

So Pythagoras works twice.

Square the three differences, add them, then take the square root.

d = √12 + 22 + 32

1 squared is 1.

2 squared is 4.

3 squared is 9.

d = √1 + 4 + 9

4 Take the square root

Add: 1 plus 4 plus 9 is 14.

d = √14

Careful!

14 is d squared.

We still take the square root.

Careful: not d = 14 ✗

14 is not a square number, so √14 is the exact answer.

d = √14

With a calculator, that is about 3.7, to the nearest tenth.

d ≈ 3.7

5 Check

Let's check: square the distance.

We get 14, the same as 1 plus 4 plus 9.

Right!

d² = 14 and 1 + 4 + 9 = 14

Going from B to A instead only changes the signs.

The squares are the same.

Right!

(1 − 2)² = 1

Let's look back.

First: plot the points.

Then: the differences.

Then: square and add.

Then: take the square root.

Last: check.

Answer
d ≈ 3.7

Your turn

Try this one yourself, then check:

Find the distance between (2, 3, 4) and (3, 4, 7)
Show the answer
d = √11 ≈ 3.3

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