Step by step
The question
Question: find the distance between (3, 1) and (11, 7).
1 Plot the points
Draw the grid.
Put both points on the grid: (3, 1)
and (11, 7).
The distance is the length of this line.
We call it d.
2 Make a right triangle
From the left point, go across.
From x = 3 to x = 11 is 8.
We call it a = 8.
Then go up.
From y = 1 to y = 7 is 6.
We call it b = 6.
Across and up make a right angle.
The distance d is the longest side.
3 Use a² + b² = c²
The rule for every right triangle: a² + b² = c².
Here c is the distance d.
Now put the numbers in: a = 8 and b = 6.
8² means 8 times 8.
That is 64.
6² means 6 times 6.
That is 36.
Write the squares: 64 + 36 = d².
64 plus 36 is 100.
d² is 100.
So d is the square root of 100.
10 times 10 is 100.
So d = 10.
The distance is 10.
4 Check
Let's check with the distance formula.
It does the same steps in one line.
Put in the numbers of (11, 7) and (3, 1).
11 minus 3 is 8.
7 minus 1 is 6.
The same as on the grid.
64 plus 36 is 100.
The square root is 10 again.
Right!
Let's look back.
First: plot the points.
Then: make a right triangle.
Then: use a² + b² = c².
Last: check.