Steply

Does Σ (-1)^(n+1) (2n + 1)/(n + 3) converge

Step by step, with the reason for every step · The divergence test · Calculus 2

Step by step

The question

Question: decide if the series converges: the sum of ((−1)ⁿ⁺¹2n + 1)/(n + 3) for n from 1 to infinity.

Σn = 1∞(−1)n+12n + 1n + 3 =

1 The term

A series adds up the terms aₙ for ever.

First look at one term, ((−1)ⁿ⁺¹2n + 1)/(n + 3).

an = (−1)n+12n + 1n + 3

The divergence test: if the terms do not go to 0, adding them for ever never settles.

The series diverges.

divergence test:
if an does not → 0,
the series diverges

2 The limit

The size, without the sign.

Divide top and bottom by n, the highest power at the bottom.

|an| = 2 + 1n1 + 3n

Every part with n at the bottom goes to 0.

as n → ∞ = 2 + 01 + 0

So the size goes to 2.

= 2

With the sign, the terms jump between about 2 and minus that.

They do not go to 0.

(−1)n+1: the sign flips

3 Decide

The terms do not go to 0.

Adding numbers close to 2 for ever never settles: the series diverges.

= diverges

Careful!

The limit of the terms tells us only about the terms, not about the sum.

Careful: the limit of the terms is not the sum

4 Check

Let's check with a calculator: the partial sums keep jumping, −0.68, 1.28, −0.7, 1.3.

They never settle.

Right!

S₁₀₀ ≈ −0.68, S₁₀₁ ≈ 1.28, S₁₀₀₀ ≈ −0.7, S₁₀₀₁ ≈ 1.3

Let's look back.

First: the term.

Then: the limit.

Then: decide.

Last: check.

Answer
= diverges

Your turn

Try this one yourself, then check:

Σn = 1∞(−1)n+12n + 13n + 3
Show the answer
diverges

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