Steply

Does Σ (n^3 + 2)/(n^2 + 1) converge

Step by step, with the reason for every step · The divergence test · Calculus 2

Step by step

The question

Question: decide if the series converges: the sum of (n³ + 2)/(n² + 1) for n from 1 to infinity.

Σn = 1∞n3 + 2n2 + 1 =

1 The term

A series adds up the terms aₙ for ever.

First look at one term, (n³ + 2)/(n² + 1).

an = n3 + 2n2 + 1

The divergence test: if the terms do not go to 0, adding them for ever never settles.

The series diverges.

divergence test:
if an does not → 0,
the series diverges

2 The limit

Divide top and bottom by n to the 2, the highest power at the bottom.

an = n + 2n21 + 1n2

Every part with n at the bottom goes to 0.

as n → ∞ = n + 01 + 0

The top still grows: the terms grow without end.

= ∞

3 Decide

The terms do not go to 0.

Adding numbers that grow for ever never settles: the series diverges.

= diverges

Careful!

The limit of the terms tells us only about the terms, not about the sum.

Careful: the limit of the terms is not the sum

4 Check

Let's check with a calculator: the sums of the first 10, 100, 1000 terms are 54.7, 5047.62, 500495.34.

They keep growing.

Right!

S₁₀ ≈ 54.7, S₁₀₀ ≈ 5047.62, S₁₀₀₀ ≈ 500495.34

Let's look back.

First: the term.

Then: the limit.

Then: decide.

Last: check.

Answer
= diverges

Your turn

Try this one yourself, then check:

Σn = 1∞3n3 + 2n2 + 1
Show the answer
diverges

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