Steply

Does Σ (n + 2)/(n^2 + 5n) converge

Step by step, with the reason for every step · Comparison tests · Calculus 2

Step by step

The question

Question: decide if the series converges: the sum of (n + 2)/(n² + 5n) for n from 1 to infinity.

Σn = 1∞n + 2n2 + 5n =

1 For big n

For big n, only the highest powers matter, top and bottom.

an = n + 2n2 + 5n ≈ nn2

Cancel: about 1 over n.

= 1n

2 The known series

We know the sum of 1/n: a p-series with p = 1.

p is 1, so it diverges.

Σn = 1∞1n: p = 1, diverges

3 Compare

The terms are not simply smaller or bigger here.

So use the limit comparison test: divide aₙ by bₙ and let n grow.

lim anbn =

Dividing by 1/n is the same as times its flip.

= n2 + 2nn2 + 5n

Top and bottom now have the same highest power with the same number: the limit is 1.

as n → ∞ = 1

The limit is a positive number.

Then the two series do the same thing: both converge, or both diverge.

limit > 0 (a number): both do the same

4 Decide

So our series diverges.

= diverges

Careful!

Smaller than a series that diverges tells us nothing.

We need bigger than a diverging one, or the limit test.

Careful: not an < 1n, so it converges ✗

5 Check

Let's check with a calculator: 100, 1000 and 10000 terms add up to about 3.85, 6.12 and 8.42.

It keeps growing.

Right!

S100 ≈ 3.8465, S1000 ≈ 6.1185, S10000 ≈ 8.4179

Let's look back.

First: for big n.

Then: the known series.

Then: compare.

Then: decide.

Last: check.

Answer
= diverges

Your turn

Try this one yourself, then check:

Σn = 1∞n + 1n2 + 5n
Show the answer
diverges

More from Comparison tests

The whole lesson: Comparison tests →