Steply

Double integral of x^2 + 4xy over 0 ≤ x ≤ 2, -1 ≤ y ≤ 1

Step by step, with the reason for every step · Double integrals over rectangles · Calculus 3

Step by step

The question

Question: find the double integral of x² + 4xy/0 ≤ x ≤ 2, −1 ≤ y ≤ 1.

∫ ∫ (x2 + 4xy) dA, 0 ≤ x ≤ 2, −1 ≤ y ≤ 1

1 Draw it

The rectangle lies on the floor: x from 0 to 2, y from −1 to 1.

The double integral adds up f over the rectangle.

Where f is below the floor, it counts as minus.

2 Find the limits

Write it as two integrals.

Inside: y from −1 to 1.

Outside: x from 0 to 2.

∫ ∫ (x2 + 4xy) dA = ∫ from 0 to 2 of ∫ from −1 to 1 of (x2 + 4xy) dy dx

Careful!

The inside integral is dy, so its limits are the y limits.

They may have x in them.

The outside limits are only numbers.

Careful: dy inside: the y limits go inside

3 The inner integral

Inside first: integrate in y.

x stays fixed, like a plain number.

Integrate each term: the power goes up by 1, and we divide by the new power.

∫ from −1 to 1 of (x2 + 4xy) dy = [x2y + 2xy2] from −1 to 1

Put in the top y = 1, then take away the bottom y = −1.

∫ from −1 to 1 of (x2 + 4xy) dy = (x2(1) + 2x(1)2) − (x2(−1) + 2x(−1)2)

Work out each part.

∫ from −1 to 1 of (x2 + 4xy) dy = (x2 + 2x) − (−x2 + 2x)

So it is 2x².

∫ from −1 to 1 of (x2 + 4xy) dy = 2x2

4 The outer integral

Now the outside integral, in x.

Its limits are numbers.

Integrate each term: the power goes up by 1, and we divide by the new power.

∫ from 0 to 2 of 2x2 dx = 2x33 from 0 to 2

Put in the top x = 2, then take away the bottom x = 0.

∫ from 0 to 2 of 2x2 dx = 2(2)33 − 2(0)33

The bottom part is 0.

So it is 16/3.

∫ from 0 to 2 of 2x2 dx = 163

5 Check

Let's check in the other order.

x first: 8/3 + 8y.

∫ from 0 to 2 of (x2 + 4xy) dx = 8 over 3 + 8y

Then y: 16/3.

The same answer.

Right!

∫ from −1 to 1 of (83 + 8y) dy = 16/3

Let's look back.

First: draw it.

Then: find the limits.

Then: the inner integral.

Then: the outer integral.

Last: check.

Answer
∫ from 0 to 2 of 2x2 dx = 163

Your turn

Try this one yourself, then check:

Find the double integral of ∫ ∫ (2x2 + 3xy) dA, 0 ≤ x ≤ 1, −1 ≤ y ≤ 1
Show the answer
43

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