Steply

Evaluate ∫ from 0 to 1 of 1/x dx

Step by step, with the reason for every step · Improper integrals · Calculus 2

Step by step

The question

Question: find the integral from 0 to 1 of 1 over x.

∫ from 0 to 1 of 1x dx =

1 Why is it improper?

Draw the curve.

At x = 0 the curve shoots up for ever: 1/0 has no value.

The area is not closed at the top.

We cannot put in 0.

So we start at a letter, t, just right of 0, and then let t shrink to 0.

x = 0 is not allowed: start at t, then let t → 0

2 Use a limit

The integral is the limit of the integral from t to 1, as t goes to 0 from the right.

∫ from 0 to 1 of 1x dx = lim t → 0⁺ ∫ from t to 1 of 1x dx

3 Integrate

1/x integrates to ln x.

The power rule cannot do it.

= lim t → 0⁺ [ ln x ] from 0 to t

4 Let t go

Put in 1, then take away the same with t.

= lim t → 0⁺ (0 − ( ln t))

As t shrinks to 0, ln t goes down without end, slowly but for ever.

ln t → ∞

5 Decide

The limit is infinity: the area has no end.

The integral diverges.

the limit = ∞

Careful!

Never put 0 in like a number: 1/0 has no value.

We let t shrink and watch where the answer goes.

Careful: not put in 0: 10 ✗

6 Check

Let's check with a calculator: from t = 0.001 the integral is about 6.91.

t = 0.001: 6.91

From a millionth, about 13.82.

It keeps growing.

Right!

t = 0.000001: 13.82

Let's look back.

First: why is it improper?.

Then: use a limit.

Then: integrate.

Then: let t go.

Then: decide.

Last: check.

Answer
Careful: not put in 0: 10 ✗

Your turn

Try this one yourself, then check:

∫ from 0 to 8 of 2x3 dx
Show the answer
diverges

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