Steply

Evaluate ∫ from 0 to 8 of 1/x^(1/3) dx

Step by step, with the reason for every step · Improper integrals · Calculus 2

Step by step

The question

Question: find the integral from 0 to 8 of 1 over (x^(1/3)).

∫ from 0 to 8 of 1x^(1/3) dx =

1 Why is it improper?

Draw the curve.

At x = 0 the curve shoots up for ever: 1/0 has no value.

The area is not closed at the top.

We cannot put in 0.

So we start at a letter, t, just right of 0, and then let t shrink to 0.

x = 0 is not allowed: start at t, then let t → 0

2 Use a limit

The integral is the limit of the integral from t to 8, as t goes to 0 from the right.

∫ from 0 to 8 of 1x^(1/3) dx = lim t → 0⁺ ∫ from t to 8 of 1x^(1/3) dx

3 Integrate

The power rule: x to the minus 1/3 becomes x to the 2/3, divided by 2/3.

= lim t → 0⁺ [ 32x^(2/3) ] from t to 8

4 Let t go

Put in 8, then take away the same with t.

= lim t → 0⁺ (6 − (32t^(2/3)))

As t shrinks to 0, 3/2 × t^(2/3) goes to 0.

32t^(2/3) → 0

The t part goes to 0.

= 6 − 0

5 Decide

The limit is a number: the integral converges to 6.

An area that goes on for ever, but adds up to 6!

= 6

Careful!

Never put 0 in like a number.

We let t shrink and watch where the answer goes.

Careful: not put in 0: 10 ✗

6 Check

Let's check with a calculator: the integral from t = 0.001 is about 5.985.

Already close to 6.

Right!

t = 0.001: 5.985

Let's look back.

First: why is it improper?.

Then: use a limit.

Then: integrate.

Then: let t go.

Then: decide.

Last: check.

Answer
Careful: not put in 0: 10 ✗

Your turn

Try this one yourself, then check:

∫ from 0 to 9 of 2√x dx
Show the answer
12

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