Steply

f(x) = -1 if x < -2, x + 1 if -2 <= x < 2, 3 if x >= 2, find f(0)

Step by step, with the reason for every step · Piecewise functions · Algebra 2

Step by step

The question

Question: find f(0) for f(x) = −1 if x < −2, x + 1 if −2 ≤ x < 2, 3 if x ≥ 2.

f(x) = −1 if x < −2
= x + 1 if −2 ≤ x < 2
= 3 if x ≥ 2

This is a piecewise function.

It has 3 rules.

Which rule we use depends on x.

Each x uses only one rule.

piecewise: a different rule for different x's
each x uses only one rule

Careful!

Not the first rule!

It is only for x less than −2, and 0 is not.

Careful: not f(0) = −1 ✗

1 Find the right piece

Let's see where each rule works on a number line.

So we use this rule: x + 1.

2 Put 0 in

Put 0 in place of x in x + 1.

f(0) = 0 + 1

0 plus 1 is 1.

f(0) = 1

So f(0) = 1.

3 Check

Let's check: does 0 fit each rule's x's?

Only one must say yes.

first rule: 0 < −2 no ✗
second rule: 0 ≥ −2 and 0 < 2 yes
third rule: 0 ≥ 2 no ✗

Only the second rule fits.

So f(0) is right!

Let's look back.

First: find the right piece.

Then: put 0 in.

Last: check.

Answer
f(0) = 1

Your turn

Try this one yourself, then check:

f(x) = −3 if x < −2, x + 3 if −2 ≤ x < 2, 4 if x ≥ 2, find f(1)
Show the answer
f(1) = 4

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