Steply

f(x) = x + 2 if x < 1, 3x - 1 if x >= 1, find f(-2)

Step by step, with the reason for every step · Piecewise functions · Algebra 2

Step by step

The question

Question: find f(−2) for f(x) = x + 2 if x < 1, 3x − 1 if x ≥ 1.

f(x) = x + 2 if x < 1
= 3x − 1 if x ≥ 1

This is a piecewise function.

It has 2 rules.

Which rule we use depends on x.

Each x uses only one rule.

piecewise: a different rule for different x's
each x uses only one rule

Careful!

Not the second rule!

It is only for x greater than or equal to 1, and −2 is not.

Careful: not f(−2) = 3(−2) − 1 = −7 ✗

1 Find the right piece

Let's see where each rule works on a number line.

So we use this rule: x + 2.

2 Put −2 in

Put −2 in place of x in x + 2.

f(−2) = −2 + 2

Start at −2.

Go up 2.

We land on 0.

f(−2) = 0

So f(−2) = 0.

3 Check

Let's check: does −2 fit each rule's x's?

Only one must say yes.

first rule: −2 < 1 yes
second rule: −2 ≥ 1 no ✗

Only the first rule fits.

So f(−2) is right!

Let's look back.

First: find the right piece.

Then: put −2 in.

Last: check.

Answer
f(−2) = 0

Your turn

Try this one yourself, then check:

f(x) = x + 5 if x < 1, 3x − 2 if x ≥ 1, find f(−1)
Show the answer
f(−1) = 4

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