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Factor 24x^3 + 81

Step by step, with the reason for every step · Sum and difference of cubes · Algebra 1

Step by step

The question

Question: factor 24x³ + 81.

24x3 + 81

1 Common factor first

Always look for a common factor first.

24 and 81 can both be divided by 3.

24, 81: all in the 3 times table

So it is 3(8x³ + 27).

= 3(8x3 + 27)

2 Write as cubes

Cubes are a number times itself three times: 2 × 2 × 2 = 8, 3 × 3 × 3 = 27.

8x³ is 2x cubed.

27 is 3 cubed.

cubes: 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000
8x3 = (2x)3, 27 = 3³

So it is a sum of two cubes: a is 2x and b is 3.

= 3((2x)3 + 33)

3 Use the pattern

Here is the pattern.

The first bracket has the same sign as the question.

In the second bracket the middle sign is the opposite one, and the last sign is always plus.

a³ + b³ = (a + b)(a² − ab + b²)
first bracket: same sign (+); middle: opposite (−); last: +

We put a = 2x and b = 3 into the pattern.

= 3[(2x + 3)((2x)2 − 2x × 3 + 32)]

Careful!

It is not (2x + 3)³.

Multiplied out, that has x² and x terms too.

Careful: not (2x + 3)³ ✗

4 Tidy up

2x squared is 4x².

2x times 3 is 6x.

3 squared is 9.

(2x)² = 4x², 2x × 3 = 6x, 3² = 9

So we get 3(2x + 3)(4x² − 6x + 9).

= 3(2x + 3)(4x2 − 6x + 9)

The second bracket can't be factored: with this pattern it never can.

5 Check

Let's check: we multiply it back out.

Each part of one bracket times each part of the other.

Check: (2x + 3)(4x2 − 6x + 9)
= 8x3 − 12x2 + 18x + 12x2 − 18x + 27
= 8x3 + 27

Then the common factor times every part.

3(8x3 + 27) = 24x3 + 81

We get 24x³ + 81 again.

So it is right!

Let's look back.

First: common factor first.

Then: write as cubes.

Then: use the pattern.

Then: tidy up.

Last: check.

Answer
= 3(2x + 3)(4x2 − 6x + 9)

Your turn

Try this one yourself, then check:

Factor 256x3 + 108
Show the answer
4(4x + 3)(16x2 − 12x + 9)

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