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Factor x^3 + x^2 - 20x = 0

Step by step, with the reason for every step · Solving by factoring · Algebra 1

Step by step

The question

Question: solve x³ + x² − 20x = 0.

x3 + x2 − 20x = 0

The right side is 0 already.

x3 + x2 − 20x = 0

1 Factor completely

Common factor first.

Every term has x.

So we take out x.

common factor: x

So it is x(x² + x − 20) = 0.

x(x2 + x − 20) = 0

Careful!

Don't divide both sides by x.

Then the answer x = 0 would be lost.

Careful: don't divide by x. We would lose x = 0.

Now the bracket.

We need two numbers.

They multiply to −20, and they add to 1.

? × ? = −20, ? + ? = 1

They multiply to a minus number, so one number is plus and one is minus.

They add to a plus number, so the bigger one is plus.

× is − → one +, one −; bigger one +

We list the pairs that make 20, smallest first.

We take the smaller from the bigger.

We need 1.

4 and 5 give 1.

Yes!

With the signs: −4 and 5.

1 × 20: 20 − 1 = 19
2 × 10: 10 − 2 = 8
4 × 5: 5 − 4 = 1 ✓

So it is x(x − 4)(x + 5) = 0.

x(x − 4)(x + 5) = 0

2 Each factor is 0

Some numbers multiply to 0.

That only happens if one of them is 0.

So we make each factor 0.

A × B × C = 0 → A = 0 or B = 0 or C = 0

Each factor with x gives a small equation.

x = 0 or x − 4 = 0 or x + 5 = 0

x = 0 is done already.

In x − 4 = 0, we add 4 on both sides.

In x + 5 = 0, we take away 5 on both sides.

x = 0 or x = 4 or x = −5

So x = 0, x = 4 and x = −5.

Three answers.

3 Check

Let's check: put each answer into x³ + x² − 20x = 0.

First x = 0.

x = 0: 03 + 02 − 20(0) = 0 + 0 + 0 = 0

Now x = 4.

x = 4: 43 + 42 − 20(4) = 64 + 16 − 80 = 0

Now x = −5.

x = −5: (−5)3 + (−5)2 − 20(−5)
= −125 + 25 + 100 = 0

We get 0 every time.

So all three answers are right!

Let's look back.

First: factor completely.

Then: each factor is 0.

Last: check.

Answer
x = 0 or x = 4 or x = −5

Your turn

Try this one yourself, then check:

Solve x3 + 11x2 + 30x = 0
Show the answer
x = 0 or x = −5 or x = −6

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