Step by step
The question
Question: solve x³ + x² − 20x = 0.
The right side is 0 already.
1 Factor completely
Common factor first.
Every term has x.
So we take out x.
So it is x(x² + x − 20) = 0.
Careful!
Don't divide both sides by x.
Then the answer x = 0 would be lost.
Now the bracket.
We need two numbers.
They multiply to −20, and they add to 1.
They multiply to a minus number, so one number is plus and one is minus.
They add to a plus number, so the bigger one is plus.
We list the pairs that make 20, smallest first.
We take the smaller from the bigger.
We need 1.
4 and 5 give 1.
Yes!
With the signs: −4 and 5.
So it is x(x − 4)(x + 5) = 0.
2 Each factor is 0
Some numbers multiply to 0.
That only happens if one of them is 0.
So we make each factor 0.
Each factor with x gives a small equation.
x = 0 is done already.
In x − 4 = 0, we add 4 on both sides.
In x + 5 = 0, we take away 5 on both sides.
So x = 0, x = 4 and x = −5.
Three answers.
3 Check
Let's check: put each answer into x³ + x² − 20x = 0.
First x = 0.
Now x = 4.
Now x = −5.
We get 0 every time.
So all three answers are right!
Let's look back.
First: factor completely.
Then: each factor is 0.
Last: check.