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Find all zeros of f(x) = x^3 + x^2 - 4x - 4

Step by step, with the reason for every step · Finding all zeros · Algebra 2

Step by step

The question

Question: find all the zeros of f(x) = x³ + x² − 4x − 4.

f(x) = x3 + x2 − 4x − 4

A zero of f is an x that makes f(x) equal 0.

A power 3 has up to three zeros.

a zero: an x where f(x) = 0

1 List the candidates

The rational root theorem: a whole or fraction zero is a factor of the last number, over a factor of the first number.

whole or fraction zero = factor of the last numberfactor of the first number

The last number is −4.

Its factors are 1, 2, 4, each with plus and minus.

factors of 4 : ±1, ±2, ±4

Careful!

Don't forget the negative ones.

−1, −2 and the others can be zeros too.

Careful: every candidate has + and −

The first number is 1.

So the candidates are just these.

candidates : ±1, ±2, ±4

2 Test the candidates

We put each candidate into f.

When we get 0, we found a zero.

Then x minus that number is a factor, like in the factor theorem lesson.

f(c) = 0 → (x − c) is a factor

Start with 1: put it in place of every x.

f(1) = 13 + 12 − 4(1) − 4

We get −6, not 0.

So 1 is not a zero.

= 1 + 1 − 4 − 4 = −6 ✗

Next −1: put it in place of every x.

f(−1) = (−1)3 + (−1)2 − 4(−1) − 4

We get 0.

So x = −1 is a zero!

= −1 + 1 + 4 − 4 = 0 zero!

3 Divide by x + 1

x = −1 is a zero, so (x + 1) is a factor.

We divide it out, with synthetic division.

x + 1 is 0 when x is −1.

So we use −1.

Then we write just the numbers in front: 1, 1, −4, −4.

The first number comes straight down: 1.

1 times −1 is −1.

Write it under the next number.

Add: 1 + (−1) is 0.

0 times −1 is 0.

Write it under the next number.

Add: −4 + 0 is −4.

−4 times −1 is 4.

Write it under the next number.

Add: −4 + 4 is 0.

The last number is the remainder: 0.

The other numbers are the answer's numbers: 1, 0, −4.

The answer starts one power lower than x³.

So f(x) = (x + 1)(x² − 4).

The other zeros come from x² − 4 = 0.

f(x) = (x + 1)(x² − 4)

4 Solve the quadratic

Now x² − 4 = 0, with the quadratic lesson.

x2 − 4 = 0

5 Get x² alone

There is no x term, so we get x² by itself.

To remove the − 4, we add 4 on both sides.

x2 − 4 + 4 = 0 + 4

0 + 4 = 4.

Now we have x² = 4.

x2 = 4

6 Square root of both sides

x squared is 4.

So x is the square root of 4, or minus it.

Minus times minus is plus, so the negative one works too.

x² = k → x = √k or x = −√k
2 × 2 = 4, (−2) × (−2) = 4

2 times 2 is 4.

So x = 2 or x = −2.

x = 2 or x = −2

7 Write all the zeros

So the zeros are −1, 2 and −2.

−1 from the test, the others from the quadratic.

zeros : x = −1 or x = 2 or x = −2

8 Check

Let's check: put 2 into f.

We get 0.

x = 2: f = 23 + 22 − 4(2) − 4 = 8 + 4 − 8 − 4
= 0

And put −2 into f.

We get 0 too.

x = −2: f = (−2)3 + (−2)2 − 4(−2) − 4
= −8 + 4 + 8 − 4 = 0

Let's look back.

First: list the candidates.

Then: test the candidates.

Then: divide by x + 1.

Then: solve the quadratic.

Then: get x² alone.

Then: square root of both sides.

Then: write all the zeros.

Last: check.

Answer
zeros : x = −1 or x = 2 or x = −2

Your turn

Try this one yourself, then check:

find all zeros of f(x) = x3 + 2x2 − 9x − 18
Show the answer
x = −2 or x = 3 or x = −3

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