Steply

Find ∫ from 0 to infinity of e^(−3x) dx, or show that it diverges

Step by step, with the reason for every step · AP Calculus BC Practice Exam 1 · AP Calculus BC

Step by step

The question

Question: find the integral from 0 to infinity of e⁻³ˣ.

∫ from 0 to ∞ of e−3x dx

1 Why it is improper

Draw the curve.

The area under it goes on to the right for ever: the top limit is infinity.

Infinity is not a number we can put in.

So we stop at a letter, t, and then let t grow without end.

∞ is not a number: use t, then let t → ∞

2 Use a limit

The integral is the limit of the integral from 0 to t, as t goes to infinity.

∫ from 0 to ∞ of e−3x dx = lim t → ∞ ∫ from 0 to t of e−3x dx

3 Integrate

e to the minus 3x integrates to itself over minus 3.

= lim t → ∞ [ −13e−3x ] from 0 to t

4 Let t go

Put in t, then take away the same with 0.

= lim t → ∞ (−13e−3t + 13e0)

As t grows, e to the minus t is 1/a huge number: it goes to 0.

e−t = 1et → 0

The first part goes to 0.

e to the 0 is 1.

= 0 + 13

5 Decide

The limit is a number: the integral converges to 1/3.

An area that goes on for ever, but adds up to 1/3!

= 13

Careful!

Never put infinity in like a number.

We let t grow and watch where the answer goes.

Careful: not put in ∞: −1∞ ✗

6 Check

Let's check with a calculator: the integral up to t = 1000 is about 0.3333.

t = 1000: 0.3333

Up to a million, about 0.3333.

Closer and closer to 0.333.

Right!

t = 1 000 000: 0.3333

Let's look back.

First: why it is improper.

Then: use a limit.

Then: integrate.

Then: let t go.

Then: decide.

Last: check.

Answer
= 13

Your turn

Try this one yourself, then check your answer:

∫ from 0 to ∞ of 5e−x dx
Show the answer
5

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