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Find the sum 27 + 18 + 12 + 8 + ...

Step by step, with the reason for every step · Series · Algebra 2

Step by step

The question

Question: find the sum 27 + 18 + 12 + 8 + and so on.

The dots at the end mean: it goes on forever.

27 + 18 + 12 + 8 + ...

1 Find the ratio

2 Look at the sums

2/3 is less than 1.

Each new term is smaller.

So the sums settle down near one number.

|r| = 23 < 1

Let's add the terms one at a time, and write each running sum: 27, 45, 57, and so on.

3 Use the sum rule

In the sum rule, r to the power n gets closer and closer to 0.

So it drops out, and the sum is the first term over 1 minus r.

S = a11 − r

Careful!

The terms go on forever, but the sum does not: each term is smaller than the one before.

Careful: forever, but the sum is not endless

Put in a₁ = 27 and r = 2/3.

S = 271 − 23

1 − 2/3 is 1/3.

So we divide by 1/3.

S = 27 ÷ 13

Dividing by 1/3 is times its flip, 3.

S = 27 × 3

So the sum is 81.

S = 81

4 Check

Let's check: we keep adding terms.

The running sums are 73.889, 76.259, 77.84.

sums: 65, 70.333, 73.889, 76.259, 77.84, ...

They get closer and closer to 81.

It works!

closer and closer to 81

Let's look back.

First: find the ratio.

Then: look at the sums.

Then: use the sum rule.

Last: check.

Answer
S = 81

Your turn

Try this one yourself, then check:

find the sum 4 + 2 + 1 + 12 + ...
Show the answer
8

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