Steply

Find the sum 9 - 3 + 1 - 1/3 + ...

Step by step, with the reason for every step · Series · Algebra 2

Step by step

The question

Question: find the sum 9 − 3 + 1 − 1/3 + and so on.

The dots at the end mean: it goes on forever.

9 − 3 + 1 − 13 + ...

1 Find the ratio

2 Look at the sums

1/3 is less than 1.

Each new term is smaller, and the sign flips.

So the sums jump up and down, but less each time: they settle down near one number.

|r| = 13 < 1

Let's add the terms one at a time, and write each running sum: 9, 6, 7, and so on.

3 Use the sum rule

In the sum rule, r to the power n gets closer and closer to 0.

So it drops out, and the sum is the first term over 1 minus r.

S = a11 − r

Careful!

r is negative.

1 minus a minus is 1 plus: 4/3, not 2/3.

Careful: not 1 − (−13) = 23 ✗

Put in a₁ = 9 and r = −1/3.

S = 91 − (−13)

1 + 1/3 is 4/3.

So we divide by 4/3.

S = 9 ÷ 43

Dividing by 4/3 is times its flip, 3/4.

S = 9 × 34

So the sum is 27/4.

S = 274

4 Check

Let's check: we keep adding terms.

The running sums are 6.741, 6.753, 6.749.

sums: 6.667, 6.778, 6.741, 6.753, 6.749, ...

They get closer and closer to 27/4.

It works!

closer and closer to 6.75

Let's look back.

First: find the ratio.

Then: look at the sums.

Then: use the sum rule.

Last: check.

Answer
S = 274

Your turn

Try this one yourself, then check:

find the sum 8 − 4 + 2 − 1 + ...
Show the answer
163

More from Series

The whole lesson: Series →