Steply

Graph r = 1 - 2 sin θ

Step by step, with the reason for every step · Polar graphs · Precalculus

Step by step

The question

Question: graph r = 1 − 2 sin θ.

θ is the angle we turn, r is how far we go out.

r = 1 − 2 sin θ

1 Check the symmetry

sin of 180° minus θ is the same as sin θ.

So the graph is its own mirror image in the y-axis.

So θ from −90° to 90° is enough: the rest is the mirror.

sin(180° − θ) = sin θ: the same r left and right of the y-axis

2 Make a table

A table: 7 angles, 30° apart, from -90° to 90°.

The angles go along the top.

−90°
−60°
−30°
0°
30°
60°
90°

sin of each angle, from the unit circle, to 2 decimal places: −1, −0.87, −0.5, and so on.

−1
−0.87
−0.5
0
0.5
0.87
1

Then r = 1 minus 2 times that.

For -90°: 1 − 2 × (−1) is 3.

3
2.7
2
1
0
−0.7
−1

3 Plot the points

The polar grid: circles 1, 2, 3 around the center, and a line for every 30°.

θ = -90°: turn -90°, that is down, then go out 3.

θ = -60°: turn -60°, go out 2.7.

And so on.

At 60°, r is negative: −0.7.

We turn 60°, then go 0.7 the other way, backwards through the center.

Careful!

A negative r is not nothing.

We go backwards, through the center, to the other side.

Careful: negative r: go the other way

4 Join and mirror

Join the points in order, with a smooth curve.

The other half is the mirror image in the y-axis.

5 Name it

1 is smaller than 2: r turns negative for some angles, and the curve makes a small loop inside.

So it is a limaçon with an inner loop.

r = 1 − 2 sin θ: a limaçon with an inner loop

6 Check

Let's check one angle we did not use: θ = 180°.

sin 180° is 0.

So r is 1: turn 180°, go out 1.

The point is on our curve.

Right!

θ = 180°: r = 1 − 2 × sin 180° = 1 − 2 × 0 = 1

Let's look back.

First: check the symmetry.

Then: make a table.

Then: plot the points.

Then: join and mirror.

Then: name it.

Last: check.

Answer
r = 1 − 2 sin θ: a limaçon with an inner loop

Your turn

Try this one yourself, then check:

r = 1 − cos θ
Show the answer
r = 1 − cos θ: a cardioid

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