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Polar graphs

Precalculus · 20 problems, easy to harder

▶ Watch the first one solved

How we do it

  1. Check the symmetry
  2. Make a table
  3. Plot the points
  4. Join the points
  5. Name it
  6. Check

The steps for Graph r = 4 cos θ. Every solution names its steps, so you always know what comes next.

Worked examples

Graph r = 4 cos θ Easy

The question

Question: graph r = 4 cos θ.

θ is the angle we turn, r is how far we go out.

r = 4 cos θ

1 Check the symmetry

cos of minus θ is the same as cos θ.

So turning up or down by the same angle gives the same r: the graph is its own mirror image in the x-axis.

For this circle, θ from 0° to 180° already draws all of it.

cos(−θ) = cos θ: the same r above and below the x-axis

2 Make a table

A table: 7 angles, 30° apart, from 0° to 180°.

The angles go along the top.

0°
30°
60°
90°
120°
150°
180°

cos of each angle, from the unit circle, to 2 decimal places: 1, 0.87, 0.5, and so on.

1
0.87
0.5
0
−0.5
−0.87
−1

Then r = 4 times that.

For 0°: 4 × 1 is 4.

4
3.5
2
0
−2
−3.5
−4

3 Plot the points

The polar grid: circles 1, 2, 3 around the center, and a line for every 30°.

θ = 0°: turn 0°, then go out 4.

θ = 30°: turn 30°, go out 3.5.

And so on.

At 120°, r is negative: −2.

We turn 120°, then go 2 the other way, backwards through the center.

Careful!

A negative r is not nothing.

We go backwards, through the center, to the other side.

Careful: negative r: go the other way

4 Join the points

Join the points in order, with a smooth curve.

5 Name it

r = 4 cos θ is a circle through the center, with diameter 4.

So it is a circle.

r = 4 cos θ: a circle

6 Check

Let's check one angle we did not use: θ = 45°.

cos 45° is 0.71.

So r is 2.8: turn 45°, go out 2.8.

The point is on our curve.

Right!

θ = 45°: r = 4 × cos 45° = 4 × 0.71 ≈ 2.8

Let's look back.

First: check the symmetry.

Then: make a table.

Then: plot the points.

Then: join the points.

Then: name it.

Last: check.

Answer
r = 4 cos θ: a circle

▶ Watch it solved

Graph r = 3 + 2 cos θ Medium

The question

Question: graph r = 3 + 2 cos θ.

θ is the angle we turn, r is how far we go out.

r = 3 + 2 cos θ

1 Check the symmetry

cos of minus θ is the same as cos θ.

So turning up or down by the same angle gives the same r: the graph is its own mirror image in the x-axis.

So θ from 0° to 180° is enough: the rest is the mirror.

cos(−θ) = cos θ: the same r above and below the x-axis

2 Make a table

A table: 7 angles, 30° apart, from 0° to 180°.

The angles go along the top.

0°
30°
60°
90°
120°
150°
180°

cos of each angle, from the unit circle, to 2 decimal places: 1, 0.87, 0.5, and so on.

1
0.87
0.5
0
−0.5
−0.87
−1

Then r = 3 plus 2 times that.

For 0°: 3 + 2 × 1 is 5.

5
4.7
4
3
2
1.3
1

3 Plot the points

The polar grid: circles 1, 2, 3 around the center, and a line for every 30°.

θ = 0°: turn 0°, then go out 5.

θ = 30°: turn 30°, go out 4.7.

And so on.

Careful!

The point is not x = θ, y = r.

We turn θ, then walk out r along that line.

Careful: turn θ first, then go out r

4 Join and mirror

Join the points in order, with a smooth curve.

The other half is the mirror image in the x-axis.

5 Name it

3 is bigger than 2: r is never 0, so the curve never reaches the center.

It has a dent: a dimple.

So it is a limaçon.

r = 3 + 2 cos θ: a limaçon

6 Check

Let's check one angle we did not use: θ = 270°.

cos 270° is 0.

So r is 3: turn 270°, go out 3.

The point is on our curve.

Right!

θ = 270°: r = 3 + 2 × cos 270° = 3 + 2 × 0 = 3

Let's look back.

First: check the symmetry.

Then: make a table.

Then: plot the points.

Then: join and mirror.

Then: name it.

Last: check.

Answer
r = 3 + 2 cos θ: a limaçon

▶ Watch it solved

Graph r = 1 + 2 cos θ Harder

The question

Question: graph r = 1 + 2 cos θ.

θ is the angle we turn, r is how far we go out.

r = 1 + 2 cos θ

1 Check the symmetry

cos of minus θ is the same as cos θ.

So turning up or down by the same angle gives the same r: the graph is its own mirror image in the x-axis.

So θ from 0° to 180° is enough: the rest is the mirror.

cos(−θ) = cos θ: the same r above and below the x-axis

2 Make a table

A table: 7 angles, 30° apart, from 0° to 180°.

The angles go along the top.

0°
30°
60°
90°
120°
150°
180°

cos of each angle, from the unit circle, to 2 decimal places: 1, 0.87, 0.5, and so on.

1
0.87
0.5
0
−0.5
−0.87
−1

Then r = 1 plus 2 times that.

For 0°: 1 + 2 × 1 is 3.

3
2.7
2
1
0
−0.7
−1

3 Plot the points

The polar grid: circles 1, 2, 3 around the center, and a line for every 30°.

θ = 0°: turn 0°, then go out 3.

θ = 30°: turn 30°, go out 2.7.

And so on.

At 150°, r is negative: −0.7.

We turn 150°, then go 0.7 the other way, backwards through the center.

Careful!

A negative r is not nothing.

We go backwards, through the center, to the other side.

Careful: negative r: go the other way

4 Join and mirror

Join the points in order, with a smooth curve.

The other half is the mirror image in the x-axis.

5 Name it

1 is smaller than 2: r turns negative for some angles, and the curve makes a small loop inside.

So it is a limaçon with an inner loop.

r = 1 + 2 cos θ: a limaçon with an inner loop

6 Check

Let's check one angle we did not use: θ = 270°.

cos 270° is 0.

So r is 1: turn 270°, go out 1.

The point is on our curve.

Right!

θ = 270°: r = 1 + 2 × cos 270° = 1 + 2 × 0 = 1

Let's look back.

First: check the symmetry.

Then: make a table.

Then: plot the points.

Then: join and mirror.

Then: name it.

Last: check.

Answer
r = 1 + 2 cos θ: a limaçon with an inner loop

▶ Watch it solved

Practice

Try each one, then open the answer. Stuck? Open the problem to watch every step.

Easy

  1. graph r = 4 cos θ
    Answer
    r = 4 cos θ: a circle
  2. graph r = 4 sin θ
    Answer
    r = 4 sin θ: a circle
  3. graph r = 2 cos θ
    Answer
    r = 2 cos θ: a circle
  4. graph r = 6 sin θ
    Answer
    r = 6 sin θ: a circle
  5. graph r = 2 + 2 cos θ
    Answer
    r = 2 + 2 cos θ: a cardioid
  6. graph r = 2 + 2 sin θ
    Answer
    r = 2 + 2 sin θ: a cardioid
  7. graph r = 3 - 3 cos θ
    Answer
    r = 3 − 3 cos θ: a cardioid
  8. graph r = 1 + sin θ
    Answer
    r = 1 + sin θ: a cardioid

Medium

  1. graph r = 3 + 2 cos θ
    Answer
    r = 3 + 2 cos θ: a limaçon
  2. graph r = 4 + 2 sin θ
    Answer
    r = 4 + 2 sin θ: a limaçon
  3. graph r = 3 - 2 cos θ
    Answer
    r = 3 − 2 cos θ: a limaçon
  4. graph r = 2 - sin θ
    Answer
    r = 2 − sin θ: a limaçon
  5. graph r = 4 + cos θ
    Answer
    r = 4 + cos θ: a limaçon
  6. graph r = 3 - 3 sin θ
    Answer
    r = 3 − 3 sin θ: a cardioid

Harder

  1. graph r = 1 + 2 cos θ
    Answer
    r = 1 + 2 cos θ: a limaçon with an inner loop
  2. graph r = 1 + 2 sin θ
    Answer
    r = 1 + 2 sin θ: a limaçon with an inner loop
  3. graph r = 2 - 3 cos θ
    Answer
    r = 2 − 3 cos θ: a limaçon with an inner loop
  4. graph r = 1 - 2 sin θ
    Answer
    r = 1 − 2 sin θ: a limaçon with an inner loop
  5. graph r = 2 + 4 cos θ
    Answer
    r = 2 + 4 cos θ: a limaçon with an inner loop
  6. graph r = 1 - 3 cos θ
    Answer
    r = 1 − 3 cos θ: a limaçon with an inner loop