Steply

Graph r = 1 - 3 cos θ

Step by step, with the reason for every step · Polar graphs · Precalculus

Step by step

The question

Question: graph r = 1 − 3 cos θ.

θ is the angle we turn, r is how far we go out.

r = 1 − 3 cos θ

1 Check the symmetry

cos of minus θ is the same as cos θ.

So turning up or down by the same angle gives the same r: the graph is its own mirror image in the x-axis.

So θ from 0° to 180° is enough: the rest is the mirror.

cos(−θ) = cos θ: the same r above and below the x-axis

2 Make a table

A table: 7 angles, 30° apart, from 0° to 180°.

The angles go along the top.

0°
30°
60°
90°
120°
150°
180°

cos of each angle, from the unit circle, to 2 decimal places: 1, 0.87, 0.5, and so on.

1
0.87
0.5
0
−0.5
−0.87
−1

Then r = 1 minus 3 times that.

For 0°: 1 − 3 × 1 is −2.

−2
−1.6
−0.5
1
2.5
3.6
4

3 Plot the points

The polar grid: circles 1, 2, 3 around the center, and a line for every 30°.

θ = 0°: turn 0°, then go out −2.

θ = 30°: turn 30°, go out −1.6.

And so on.

Careful!

A negative r is not nothing.

We go backwards, through the center, to the other side.

Careful: negative r: go the other way

4 Join and mirror

Join the points in order, with a smooth curve.

The other half is the mirror image in the x-axis.

5 Name it

1 is smaller than 3: r turns negative for some angles, and the curve makes a small loop inside.

So it is a limaçon with an inner loop.

r = 1 − 3 cos θ: a limaçon with an inner loop

6 Check

Let's check one angle we did not use: θ = 270°.

cos 270° is 0.

So r is 1: turn 270°, go out 1.

The point is on our curve.

Right!

θ = 270°: r = 1 − 3 × cos 270° = 1 − 3 × 0 = 1

Let's look back.

First: check the symmetry.

Then: make a table.

Then: plot the points.

Then: join and mirror.

Then: name it.

Last: check.

Answer
r = 1 − 3 cos θ: a limaçon with an inner loop

Your turn

Try this one yourself, then check:

r = 1 − 4 sin θ
Show the answer
r = 1 − 4 sin θ: a limaçon with an inner loop

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