Steply

Graph x > -1 and y <= -x + 2

Step by step, with the reason for every step · Systems of inequalities · Algebra 1

Step by step

The question

Question: graph x > −1 and y ≤ −x + 2.

① x > −1 and ② y ≤ −x + 2

We shade the answer of each one.

Where both are shaded, both are true.

answer = the part shaded twice

1 Graph ①

Draw the grid.

①: The sign is more than, with no "or equal to".

So the line is dashed.

① > → dashed line

x = −1 is a vertical line through −1 on the x-axis.

Straight up and down: dashed.

Which side?

We test one point: (0, 0).

Put x = 0 and y = 0 into ①.

① 0 > −1 true

Is 0 more than −1?

Yes, true.

So we shade the side with (0, 0), in red.

2 Graph ②

②: The sign has "or equal to".

So the line is solid.

② ≤ → solid line

b = 2.

Start on the y-axis at 2.

m = −1.

Go right 1,

then down 1.

Dot.

Join the dots: solid.

Which side?

We test one point: (0, 0).

Put x = 0 and y = 0 into ②.

② 0 ≤ −(0) + 2
0 ≤ 2 true

Is 0 less than or equal to 2?

Yes, true.

So we shade the side with (0, 0), in blue.

3 Where both are shaded

This part is shaded twice.

It is the answer.

Careful!

The answer is not everything we shaded.

Only the part shaded twice works in both.

Careful: not every shaded part ✗

4 Check

Let's check with a point in the purple part: (1, −1).

Put it into ①.

① 1 > −1 true

Now ②.

② −1 ≤ −1 + 2
−1 ≤ 1 true

True in both!

So the answer is right.

Let's look back.

First: graph ①.

Then: graph ②.

Then: where both are shaded.

Last: check.

Answer
0 ≤ 2 true

Your turn

Try this one yourself, then check:

Graph x > −4 and y ≤ −x + 3
Show the answer
the part shaded twice

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