Worked examples
The question
Question: graph y > 2x โ 1 and y โค โx + 3.
โ y > 2x โ 1 and โก y โค โx + 3
We shade the answer of each one.
Where both are shaded, both are true.
answer = the part shaded twice
1 Graph โ
Draw the grid.
โ : The sign is more than, with no "or equal to".
So the line is dashed.
โ > โ dashed line
b = โ1.
Start on the y-axis at โ1.
m = 2.
Go right 1,
then up 2.
Dot.
Join the dots: dashed.
Which side?
We test one point: (0, 0).
Put x = 0 and y = 0 into โ .
โ 0 > 2(0) โ 1
0 > โ1 true
Is 0 more than โ1?
Yes, true.
So we shade the side with (0, 0), in red.
2 Graph โก
โก: The sign has "or equal to".
So the line is solid.
โก โค โ solid line
b = 3.
Start on the y-axis at 3.
m = โ1.
Go right 1,
then down 1.
Dot.
Join the dots: solid.
Which side?
We test one point: (0, 0).
Put x = 0 and y = 0 into โก.
โก 0 โค โ(0) + 3
0 โค 3 true
Is 0 less than or equal to 3?
Yes, true.
So we shade the side with (0, 0), in blue.
3 Where both are shaded
This part is shaded twice.
It is the answer.
Careful!
The answer is not everything we shaded.
Only the part shaded twice works in both.
Careful: not every shaded part โ
4 Check
Let's check with a point in the purple part: (โ1, โ1).
Put it into โ .
โ โ1 > 2(โ1) โ 1
โ1 > โ3 true
Now โก.
โก โ1 โค โ(โ1) + 3
โ1 โค 4 true
True in both!
So the answer is right.
Let's look back.
First: graph โ .
Then: graph โก.
Then: where both are shaded.
Last: check.
โถ Watch it solved
The question
Question: graph y < 3 and y > x โ 1.
โ y < 3 and โก y > x โ 1
We shade the answer of each one.
Where both are shaded, both are true.
answer = the part shaded twice
1 Graph โ
Draw the grid.
โ : The sign is less than, with no "or equal to".
So the line is dashed.
โ < โ dashed line
b = 3.
Start on the y-axis at 3.
A flat line through the dot: dashed.
Which side?
We test one point: (0, 0).
Put x = 0 and y = 0 into โ .
โ 0 < 3 true
Is 0 less than 3?
Yes, true.
So we shade the side with (0, 0), in red.
2 Graph โก
โก: The sign is more than, with no "or equal to".
So the line is dashed.
โก > โ dashed line
b = โ1.
Start on the y-axis at โ1.
m = 1.
Go right 1,
then up 1.
Dot.
Join the dots: dashed.
Which side?
We test one point: (0, 0).
Put x = 0 and y = 0 into โก.
โก 0 > 0 โ 1
0 > โ1 true
Is 0 more than โ1?
Yes, true.
So we shade the side with (0, 0), in blue.
3 Where both are shaded
This part is shaded twice.
It is the answer.
Careful!
The answer is not everything we shaded.
Only the part shaded twice works in both.
Careful: not every shaded part โ
4 Check
Let's check with a point in the purple part: (โ1, โ1).
Put it into โ .
โ โ1 < 3 true
Now โก.
โก โ1 > (โ1) โ 1
โ1 > โ2 true
True in both!
So the answer is right.
Let's look back.
First: graph โ .
Then: graph โก.
Then: where both are shaded.
Last: check.
โถ Watch it solved
The question
Question: graph x โ y > 3 and y < 2.
โ x โ y > 3 and โก y < 2
We shade the answer of each one.
Where both are shaded, both are true.
answer = the part shaded twice
1 Crossing points of โ
On the x-axis, y = 0.
Put 0 in place of y.
x โ 1 ร 0 = 3
1 times 0 is 0.
Taking away 0 changes nothing.
So x = 3.
x = 3
On the y-axis, x = 0.
Put 0 in place of x.
0 โ y = 3
0 minus y is โy.
โy = 3
โy means โ1 times y.
We want just y.
To remove times โ1, we divide by โ1.
We do it on both sides, so they stay equal.
โyโ1 = 3โ1
โ1 divided by โ1 is 1.
So just y is left.
Plus over minus is minus.
3 divided by โ1 is โ3.
3โ1 = โ3
So y = โ3.
So line โ crosses the axes at (3, 0) and (0, โ3).
y = โ3
2 Graph โ
Draw the grid.
โ : The sign is more than, with no "or equal to".
So the line is dashed.
โ > โ dashed line
Put the two crossing points on the grid,
and join them: dashed.
Which side?
We test one point: (0, 0).
Put x = 0 and y = 0 into โ .
โ 0 โ 0 > 3
0 > 3 false
Is 0 more than 3?
No, false.
Careful!
The sign alone does not say above or below.
When y has a minus in front, it can turn.
The test point tells us.
Careful: > does not always mean above
So we shade the other side, away from (0, 0), in red.
3 Graph โก
โก: The sign is less than, with no "or equal to".
So the line is dashed.
โก < โ dashed line
b = 2.
Start on the y-axis at 2.
A flat line through the dot: dashed.
Which side?
We test one point: (0, 0).
Put x = 0 and y = 0 into โก.
โก 0 < 2 true
Is 0 less than 2?
Yes, true.
So we shade the side with (0, 0), in blue.
4 Where both are shaded
This part is shaded twice.
It is the answer.
5 Check
Let's check with a point in the purple part: (1, โ3).
Put it into โ .
โ 1 โ (โ3) > 3
4 > 3 true
Now โก.
โก โ3 < 2 true
True in both!
So the answer is right.
Let's look back.
First: crossing points of โ .
Then: graph โ .
Then: graph โก.
Then: where both are shaded.
Last: check.
โถ Watch it solved