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Systems of inequalities

Algebra 1 ยท 21 problems, easy to harder

โ–ถ Watch the first one solved

How we do it

  1. Crossing points of โ‘ 
  2. Graph โ‘ 
  3. Graph โ‘ก
  4. Where both are shaded
  5. Check

The steps for Graph x - y > 3 and y < 2. Every solution names its steps, so you always know what comes next.

Worked examples

Graph y > 2x - 1 and y <= -x + 3 Easy

The question

Question: graph y > 2x โˆ’ 1 and y โ‰ค โˆ’x + 3.

โ‘  y > 2x โˆ’ 1 and โ‘ก y โ‰ค โˆ’x + 3

We shade the answer of each one.

Where both are shaded, both are true.

answer = the part shaded twice

1 Graph โ‘ 

Draw the grid.

โ‘ : The sign is more than, with no "or equal to".

So the line is dashed.

โ‘  > โ†’ dashed line

b = โˆ’1.

Start on the y-axis at โˆ’1.

m = 2.

Go right 1,

then up 2.

Dot.

Join the dots: dashed.

Which side?

We test one point: (0, 0).

Put x = 0 and y = 0 into โ‘ .

โ‘  0 > 2(0) โˆ’ 1
0 > โˆ’1 true

Is 0 more than โˆ’1?

Yes, true.

So we shade the side with (0, 0), in red.

2 Graph โ‘ก

โ‘ก: The sign has "or equal to".

So the line is solid.

โ‘ก โ‰ค โ†’ solid line

b = 3.

Start on the y-axis at 3.

m = โˆ’1.

Go right 1,

then down 1.

Dot.

Join the dots: solid.

Which side?

We test one point: (0, 0).

Put x = 0 and y = 0 into โ‘ก.

โ‘ก 0 โ‰ค โˆ’(0) + 3
0 โ‰ค 3 true

Is 0 less than or equal to 3?

Yes, true.

So we shade the side with (0, 0), in blue.

3 Where both are shaded

This part is shaded twice.

It is the answer.

Careful!

The answer is not everything we shaded.

Only the part shaded twice works in both.

Careful: not every shaded part โœ—

4 Check

Let's check with a point in the purple part: (โˆ’1, โˆ’1).

Put it into โ‘ .

โ‘  โˆ’1 > 2(โˆ’1) โˆ’ 1
โˆ’1 > โˆ’3 true

Now โ‘ก.

โ‘ก โˆ’1 โ‰ค โˆ’(โˆ’1) + 3
โˆ’1 โ‰ค 4 true

True in both!

So the answer is right.

Let's look back.

First: graph โ‘ .

Then: graph โ‘ก.

Then: where both are shaded.

Last: check.

Answer
0 โ‰ค 3 true

โ–ถ Watch it solved

Graph y < 3 and y > x - 1 Medium

The question

Question: graph y < 3 and y > x โˆ’ 1.

โ‘  y < 3 and โ‘ก y > x โˆ’ 1

We shade the answer of each one.

Where both are shaded, both are true.

answer = the part shaded twice

1 Graph โ‘ 

Draw the grid.

โ‘ : The sign is less than, with no "or equal to".

So the line is dashed.

โ‘  < โ†’ dashed line

b = 3.

Start on the y-axis at 3.

A flat line through the dot: dashed.

Which side?

We test one point: (0, 0).

Put x = 0 and y = 0 into โ‘ .

โ‘  0 < 3 true

Is 0 less than 3?

Yes, true.

So we shade the side with (0, 0), in red.

2 Graph โ‘ก

โ‘ก: The sign is more than, with no "or equal to".

So the line is dashed.

โ‘ก > โ†’ dashed line

b = โˆ’1.

Start on the y-axis at โˆ’1.

m = 1.

Go right 1,

then up 1.

Dot.

Join the dots: dashed.

Which side?

We test one point: (0, 0).

Put x = 0 and y = 0 into โ‘ก.

โ‘ก 0 > 0 โˆ’ 1
0 > โˆ’1 true

Is 0 more than โˆ’1?

Yes, true.

So we shade the side with (0, 0), in blue.

3 Where both are shaded

This part is shaded twice.

It is the answer.

Careful!

The answer is not everything we shaded.

Only the part shaded twice works in both.

Careful: not every shaded part โœ—

4 Check

Let's check with a point in the purple part: (โˆ’1, โˆ’1).

Put it into โ‘ .

โ‘  โˆ’1 < 3 true

Now โ‘ก.

โ‘ก โˆ’1 > (โˆ’1) โˆ’ 1
โˆ’1 > โˆ’2 true

True in both!

So the answer is right.

Let's look back.

First: graph โ‘ .

Then: graph โ‘ก.

Then: where both are shaded.

Last: check.

Answer
0 > โˆ’1 true

โ–ถ Watch it solved

Graph x - y > 3 and y < 2 Harder

The question

Question: graph x โˆ’ y > 3 and y < 2.

โ‘  x โˆ’ y > 3 and โ‘ก y < 2

We shade the answer of each one.

Where both are shaded, both are true.

answer = the part shaded twice

1 Crossing points of โ‘ 

On the x-axis, y = 0.

Put 0 in place of y.

x โˆ’ 1 ร— 0 = 3

1 times 0 is 0.

Taking away 0 changes nothing.

So x = 3.

x = 3

On the y-axis, x = 0.

Put 0 in place of x.

0 โˆ’ y = 3

0 minus y is โˆ’y.

โˆ’y = 3

โˆ’y means โˆ’1 times y.

We want just y.

To remove times โˆ’1, we divide by โˆ’1.

We do it on both sides, so they stay equal.

โˆ’yโˆ’1 = 3โˆ’1

โˆ’1 divided by โˆ’1 is 1.

So just y is left.

Plus over minus is minus.

3 divided by โˆ’1 is โˆ’3.

3โˆ’1 = โˆ’3

So y = โˆ’3.

So line โ‘  crosses the axes at (3, 0) and (0, โˆ’3).

y = โˆ’3

2 Graph โ‘ 

Draw the grid.

โ‘ : The sign is more than, with no "or equal to".

So the line is dashed.

โ‘  > โ†’ dashed line

Put the two crossing points on the grid,

and join them: dashed.

Which side?

We test one point: (0, 0).

Put x = 0 and y = 0 into โ‘ .

โ‘  0 โˆ’ 0 > 3
0 > 3 false

Is 0 more than 3?

No, false.

Careful!

The sign alone does not say above or below.

When y has a minus in front, it can turn.

The test point tells us.

Careful: > does not always mean above

So we shade the other side, away from (0, 0), in red.

3 Graph โ‘ก

โ‘ก: The sign is less than, with no "or equal to".

So the line is dashed.

โ‘ก < โ†’ dashed line

b = 2.

Start on the y-axis at 2.

A flat line through the dot: dashed.

Which side?

We test one point: (0, 0).

Put x = 0 and y = 0 into โ‘ก.

โ‘ก 0 < 2 true

Is 0 less than 2?

Yes, true.

So we shade the side with (0, 0), in blue.

4 Where both are shaded

This part is shaded twice.

It is the answer.

5 Check

Let's check with a point in the purple part: (1, โˆ’3).

Put it into โ‘ .

โ‘  1 โˆ’ (โˆ’3) > 3
4 > 3 true

Now โ‘ก.

โ‘ก โˆ’3 < 2 true

True in both!

So the answer is right.

Let's look back.

First: crossing points of โ‘ .

Then: graph โ‘ .

Then: graph โ‘ก.

Then: where both are shaded.

Last: check.

Answer
โ‘ก 0 < 2 true

โ–ถ Watch it solved

Practice

Try each one, then open the answer. Stuck? Open the problem to watch every step.

Easy

  1. graph y > 2x - 1 and y <= -x + 3
    Answer
    0 โ‰ค 3 true
  2. graph y < x + 2 and y > -x
    Answer
    โ‘ก 0 > โˆ’1 true
  3. graph y >= x - 1 and y < -2x + 4
    Answer
    0 < 4 true
  4. graph y > -x + 1 and y < 2x + 3
    Answer
    0 < 3 true
  5. graph y <= 2x + 1 and y > -x - 2
    Answer
    0 > โˆ’2 true
  6. graph y < 3x and y > x - 2
    Answer
    0 > โˆ’2 true
  7. graph y > x and y < -x + 4
    Answer
    0 < 4 true
  8. graph y >= -2x + 1 and y <= x + 3
    Answer
    0 โ‰ค 3 true

Medium

  1. graph y < 3 and y > x - 1
    Answer
    0 > โˆ’1 true
  2. graph x > -1 and y <= -x + 2
    Answer
    0 โ‰ค 2 true
  3. graph y >= -1 and y < 1/2x + 2
    Answer
    0 < 2 true
  4. graph y > 1/2x - 1 and y < -x + 3
    Answer
    0 < 3 true
  5. graph x <= 2 and y > -2
    Answer
    โ‘ก 0 > โˆ’2 true
  6. graph y <= -1/2x + 2 and y > x - 3
    Answer
    0 > โˆ’3 true
  7. graph y > -2 and y < -1/3x + 1
    Answer
    0 < 1 true

Harder

  1. graph x - y > 3 and y < 2
    Answer
    โ‘ก 0 < 2 true
  2. graph x + 2y <= 4 and y > x - 2
    Answer
    0 > โˆ’2 true
  3. graph 2x + y > 2 and x - y < 1
    Answer
    0 < 1 true
  4. graph y > x - 2 and y < x + 3
    Answer
    0 < 3 true
  5. graph 3x - 2y < 6 and y < 1
    Answer
    โ‘ก 0 < 1 true
  6. graph y > x + 2 and y < x - 1
    Answer
    Nothing is shaded twice: no solution.