Steply

Graph y^2 = 12x

Step by step, with the reason for every step · Parabola · Precalculus

Step by step

The question

Question: find the focus and the directrix of y² = 12x.

y2 = 12x

1 Find p

Compare with the parabola rule: y² = 4px.

rule: y² = 4px

So 4p is the number in front of x: 4p = 12.

4p = 12

Careful!

12 is 4p, not p.

We still divide by 4.

Careful: not p = 12 ✗

To remove times 4, we divide by 4.

We do it on both sides, so they stay equal.

4p4 = 124

4 divided by 4 is 1.

So just p is left.

12 divided by 4 is 3.

So p = 3.

p = 3

2 Focus and directrix

There are no brackets: just y² and x.

So the vertex is (0, 0).

vertex = (0, 0)

p is positive.

So the parabola opens right.

p > 0: opens right

The focus is 3 to the right of the vertex, inside the curve: (3, 0).

focus = (3, 0)

The directrix is the upright line 3 on the other side of the vertex: x = −3.

directrix: x = −3

So the focus is (3, 0) and the directrix is x = −3.

focus (3, 0) and x = −3

3 Draw it

Draw the grid.

The vertex (0, 0),

the focus (3, 0),

and the directrix x = −3, dashed.

The parabola opens right, around the focus.

4 Check

Let's check with a point on the parabola, level with the focus: (3, 6).

Is it on the parabola?

Put it in: 36 and 36.

Yes!

6² = 12 × 3 → 36 = 36

Its distance to the focus: 6.

Its distance to the directrix: 6 too.

The same distance.

That is what makes a parabola.

Right!

to the focus 6, to the directrix 6

Let's look back.

First: find p.

Then: focus and directrix.

Then: draw it.

Last: check.

Answer
focus (3, 0) and x = −3

Your turn

Try this one yourself, then check:

Find the focus and the directrix of y2 = 4x
Show the answer
focus (1, 0) and x = −1

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