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Integrate ∫ (3x + 2)^4 dx

Step by step, with the reason for every step · u-substitution · Calculus

Step by step

The question

Question: find the integral of (3x + 2)⁴.

∫ (3x + 2)4 dx =

1 Choose u

The inside: 3x + 2.

Call it u.

Its derivative is just a number, 3.

u = 3x + 2

2 Find du

The power rule: du/dx = 3.

dudx = 3

Multiply both sides by dx: du = 3 dx.

A small change in u is 3 times a small change in x.

du = 3 dx

We have just dx.

Divide both sides by 3: dx = du over 3.

dx = du3

3 Write it with u

3x + 2 becomes u, and dx becomes a third of du.

A number in front can wait outside the integral.

= 13∫ u4 du

Careful!

dx is not du.

It is only a third of du.

Careful: not dx = du ✗

4 Integrate

Integrate: add 1 to the power, divide by the new power.

4 plus 1 is 5.

= 13 × u55 + C

Multiply the numbers: 1/3 times 1/5 is 1/15.

= u515 + C
13 × 15 = 115

5 Put x back

The question was in x, so the answer is in x too.

Put 3x + 2 back in place of u.

So the answer is (3x + 2)⁵ over 15 + C.

= (3x + 2)515 + C

6 Check

Let's check: take the derivative of our answer with the chain rule.

The power comes down and cancels the number below.

Then times the inside's slope, 3.

derivative: 13(3x + 2)4 × 3

That is (3x + 2)⁴: the question again.

Right!

= (3x + 2)4

Let's look back.

First: choose u.

Then: find du.

Then: write it with u.

Then: integrate.

Then: put x back.

Last: check.

Answer
= (3x + 2)515 + C

Your turn

Try this one yourself, then check:

Find the integral of ∫ (4x + 1)3 dx
Show the answer
(4x + 1)416 + C

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