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Integrate ∫ 3x^2(x^3 - 2)^4 dx

Step by step, with the reason for every step · u-substitution · Calculus

Step by step

The question

Question: find the integral of 3x² times (x³ − 2)⁴.

∫ 3x2(x3 − 2)4 dx =

1 Choose u

The inside: x³ − 2.

Call it u.

Its derivative is 3x², and 3x² is outside.

A good sign: u′ is there, or nearly.

u = x3 − 2

2 Find du

The power rule: du/dx = 3x².

dudx = 3x2

Multiply both sides by dx: du = 3x² dx.

A small change in u is 3x² times a small change in x.

du = 3x2 dx

3 Write it with u

x³ − 2 becomes u, and 3x² dx becomes du.

= ∫ u4 du

4 Integrate

Integrate: add 1 to the power, divide by the new power.

4 plus 1 is 5.

= u55 + C

5 Put x back

The question was in x, so the answer is in x too.

Put x³ − 2 back in place of u.

So the answer is (x³ − 2)⁵ over 5 + C.

= (x3 − 2)55 + C

6 Check

Let's check: take the derivative of our answer with the chain rule.

The power comes down and cancels the number below.

Then times the inside's slope, 3x².

derivative: (x3 − 2)4 × 3x2

That is 3x²(x³ − 2)⁴: the question again.

Right!

= 3x2(x3 − 2)4

Let's look back.

First: choose u.

Then: find du.

Then: write it with u.

Then: integrate.

Then: put x back.

Last: check.

Answer
= (x3 − 2)55 + C

Your turn

Try this one yourself, then check:

Find the integral of ∫ 3x2(x3 − 4)5 dx
Show the answer
(x3 − 4)66 + C

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