Steply

Interval of convergence of Σ n! x^n

Step by step, with the reason for every step · Power series · Calculus 2

Step by step

The question

Question: find for which x the series converges: the sum of n factorial xⁿ.

Σn = 1∞n!xn =

1 The ratio

Use the ratio test.

x can be negative, so we take sizes, with bars.

ratio test: L = lim |an+1an| < 1

Divide the next term by this one.

x to the n + 1, over x to the n, leaves one x.

The factorials leave n + 1.

|an+1an| = |x| × (n + 1)

2 The limit

n + 1 grows without end.

Unless x is 0, L is infinity.

L = ∞ (if x ≠ 0)

3 The interval

The series converges only at x = 0: the radius is 0.

= only x = 0

Careful!

x = 0 still works: every term is 0 there.

Careful: not L = ∞, so no x works ✗

4 Check

Let's check: at x = 0 every term has a 0 in it, so the sum is 0: it converges there.

Right!

x = 0: every term is 0, the sum is 0

Let's look back.

First: the ratio.

Then: the limit.

Then: the interval.

Last: check.

Answer
= only x = 0

Your turn

Try this one yourself, then check:

Σn = 1∞n!(x − 3)n
Show the answer
only x = 3

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