Step by step
The question
Question: is (0, −2) a solution of y = 3x − 2 and x + y = 1.
① y = 3x − 2 and ② x + y = 1
is (0, −2) a solution?
1 Read x and y
The first number is always x.
The second is y.
So x = 0 and y = −2.
(0, −2) → x = 0, y = −2
Careful!
Do not swap them.
The first number in (0, −2) is x.
Careful: not x = −2, y = 0 ✗
2 Check ①
①: Put x = 0 and y = −2 in.
(−2) =? 3(0) − 2
Work out each side.
−2 =? 0 − 2
Is −2 equal to −2?
Yes.
True!
−2 = −2 true
3 Check ②
②: Put x = 0 and y = −2 in.
0 + (−2) =? 1
Work out each side.
0 − 2 =? 1
Is −2 equal to 1?
No.
That is false.
−2 ≠ 1 false ✗
② is false.
A solution must make both true.
So (0, −2) is not a solution of the system.
(0, −2) is not a solution
Let's look back.
First: read x and y.
Then: check ①.
Last: check ②.
Answer
(0, −2) is not a solution