The question
Question: is (2, 1) a solution of 3x + y = 7.
3x + y = 7
is (2, 1) a solution?
1 Read x and y
The first number is always x.
The second is y.
So x = 2 and y = 1.
(2, 1) → x = 2, y = 1
Careful!
Do not swap them.
The first number in (2, 1) is x.
Careful: not x = 1, y = 2 ✗
2 Put them in
Put x = 2 and y = 1 in.
3(2) + 1 =? 7
Work out each side.
6 + 1 =? 7
Is 7 equal to 7?
Yes.
True!
7 = 7 true
It is true.
So (2, 1) is a solution.
(2, 1) is a solution
Let's look back.
First: read x and y.
Last: put them in.
Answer (2, 1) is a solution
▶ Watch it solved
The question
Question: is (−2, 3) a solution of y = −x + 1.
y = −x + 1
is (−2, 3) a solution?
1 Read x and y
The first number is always x.
The second is y.
So x = −2 and y = 3.
(−2, 3) → x = −2, y = 3
Careful!
Do not swap them.
The first number in (−2, 3) is x.
Careful: not x = 3, y = −2 ✗
2 Put them in
Put x = −2 and y = 3 in.
3 =? −(−2) + 1
Work out each side.
3 =? 2 + 1
Is 3 equal to 3?
Yes.
True!
3 = 3 true
It is true.
So (−2, 3) is a solution.
(−2, 3) is a solution
Let's look back.
First: read x and y.
Last: put them in.
Answer (−2, 3) is a solution
▶ Watch it solved
The question
Question: is (1, 2) a solution of y > 2x − 1.
y > 2x − 1
is (1, 2) a solution?
1 Read x and y
The first number is always x.
The second is y.
So x = 1 and y = 2.
(1, 2) → x = 1, y = 2
Careful!
Do not swap them.
The first number in (1, 2) is x.
Careful: not x = 2, y = 1 ✗
2 Put them in
Put x = 1 and y = 2 in.
2 >? 2(1) − 1
Work out each side.
2 >? 2 − 1
Is 2 more than 1?
Yes.
True!
2 > 1 true
It is true.
So (1, 2) is a solution.
(1, 2) is a solution
Let's look back.
First: read x and y.
Last: put them in.
Answer (1, 2) is a solution
▶ Watch it solved
