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Is (2, 1) a solution of y > x + 1 and x + y < 5

Step by step, with the reason for every step · Checking a solution · Algebra 1

Step by step

The question

Question: is (2, 1) a solution of y > x + 1 and x + y < 5.

① y > x + 1 and ② x + y < 5
is (2, 1) a solution?

1 Read x and y

The first number is always x.

The second is y.

So x = 2 and y = 1.

(2, 1) → x = 2, y = 1

Careful!

Do not swap them.

The first number in (2, 1) is x.

Careful: not x = 1, y = 2 ✗

2 Check ①

①: Put x = 2 and y = 1 in.

1 >? 2 + 1

Work out each side.

Is 1 more than 3?

No.

That is false.

1 > 3 false ✗

3 Check ②

②: Put x = 2 and y = 1 in.

2 + 1 <? 5

Work out each side.

Is 3 less than 5?

Yes.

True!

3 < 5 true

① is false.

A solution must make both true.

So (2, 1) is not a solution of the system of inequalities.

(2, 1) is not a solution

Let's look back.

First: read x and y.

Then: check ①.

Last: check ②.

Answer
(2, 1) is not a solution

Your turn

Try this one yourself, then check:

is (1, 4) a solution of y > x + 5 and x + y < 7
Show the answer
(1, 4) is not a solution

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