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The question
Question: is (2, −1) a solution of 3x − y = 7 and x − 2y = 4.
① 3x − y = 7 and ② x − 2y = 4
is (2, −1) a solution?
1 Read x and y
The first number is always x.
The second is y.
So x = 2 and y = −1.
(2, −1) → x = 2, y = −1
Careful!
Do not swap them.
The first number in (2, −1) is x.
Careful: not x = −1, y = 2 ✗
2 Check ①
①: Put x = 2 and y = −1 in.
3(2) − (−1) =? 7
Work out each side.
6 + 1 =? 7
Is 7 equal to 7?
Yes.
True!
7 = 7 true
3 Check ②
②: Put x = 2 and y = −1 in.
2 − 2(−1) =? 4
Work out each side.
2 + 2 =? 4
Is 4 equal to 4?
Yes.
True!
4 = 4 true
Both are true.
So (2, −1) is a solution of the system.
(2, −1) is a solution
Let's look back.
First: read x and y.
Then: check ①.
Last: check ②.
Answer
(2, −1) is a solution