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Is f(x) = (x^2 - 9)/(x - 3) continuous at x = 3

Step by step, with the reason for every step · Continuity · Calculus

Step by step

The question

Question: decide if f(x) = (x² − 9)/(x − 3) is continuous at x = 3.

f(x) = x2 − 9x − 3

Continuous at x = 3 means three things are true.

One: f(3) has a value.

Two: the limit there exists.

Three: they are equal.

1. f(3) has a value
2. the limit at 3 exists
3. limit = f(3)

1 Does f have a value?

Put 3 in place of x.

f(3) = 32 − 93 − 3 = 00

The bottom is 0.

We cannot divide by 0.

So f(3) has no value.

0 over 0: no value

Careful!

The limit does exist here: it is 6.

But f(3) has no value.

The graph has a hole.

Careful: the limit 6 is not enough

Check 1 is false.

We can stop here: one false check is enough.

1. f(3): no value ✗

So f is not continuous at x = 3.

= f is not continuous at x = 3

2 Check

Let's check on the graph.

The graph comes to height 6 from both sides, but there is a hole at x = 3.

We must lift the pen.

Right!

Let's look back.

First: does f have a value?.

Last: check.

Answer
= f is not continuous at x = 3

Your turn

Try this one yourself, then check:

f(x) = x2 − 6x + 8x − 2
Show the answer
not continuous at x = 2

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