Steply

Solve f(x) = 2x - 1 for x < 3, x + 2 for x >= 3, continuous at x = 3

Step by step, with the reason for every step · Continuity · Calculus

Step by step

The question

Question: decide if this f(x) is continuous at x = 3.

f(x) = 2x − 1 if x < 3
= x + 2 if x ≥ 3

Continuous at x = 3 means three things are true.

One: f(3) has a value.

Two: the limit there exists.

Three: they are equal.

1. f(3) has a value
2. the limit at 3 exists
3. limit = f(3)

1 Does f have a value?

Which piece holds x = 3?

The one with x ≥ 3.

So f(3) = 5.

f(3) = 3 + 2 = 5

Careful!

Having a value is not enough.

The graph must also arrive at that height from both sides.

Careful: a value at 3 is not enough

Check 1 is true: f(3) is 5.

1. f(3) = 5

2 Does the limit exist?

From the left, we use 2x − 1.

We get 5.

lim x → 3⁻ f(x) = 2(3) − 1 = 6 − 1 = 5

From the right, we use x + 2.

We get 5.

lim x → 3⁺ f(x) = 3 + 2 = 5

Both sides give 5.

Check 2 is true: the limit exists.

2. left = right = 5

3 Are they equal?

The limit is 5, and f(3) is 5.

They are equal.

Check 3 is true.

3. limit = 5 = f(3)

All three checks are true.

So f is continuous at x = 3.

= f is continuous at x = 3

4 Check

Let's check on the graph.

The first piece comes in from the left.

The second piece goes on from the same point.

No lifting the pen.

Right!

Let's look back.

First: does f have a value?.

Then: does the limit exist?.

Then: are they equal?.

Last: check.

Answer
= f is continuous at x = 3

Your turn

Try this one yourself, then check:

Decide if this f(x) is continuous at f(x) = 5x − 4 if x < 4; 3x + 4 if x ≥ 4
Show the answer
continuous at x = 4

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