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Juniors: 30 bus, 20 car, 10 walk; seniors: 20 bus, 35 car, 15 walk…

Step by step, with the reason for every step · AP Statistics Practice Exam 1 · AP Statistics

Step by step

The question

Question: junior: 30 bus, 20 car, 10 walk; senior: 20 bus, 35 car, 15 walk: at the 5% level, is the answer linked to the group?

junior: 30 bus, 20 car, 10 walk; senior: 20 bus, 35 car, 15 walk; α = 0.05

There are four choices.

First we solve it, the normal way.

Then we pick.

1 Write the hypotheses

H₀ is the "nothing new" idea.

Here: the group and the answer are independent.

H0 : the group and the answer are independent

Hₐ is what we want to show.

Here: the group and the answer are linked.

Ha : the group and the answer are linked

Independent means no link: the answer does not depend on the group.

independent: no link, the answer does not depend on the group

2 Totals

The counts in a table.

Each row's total: junior, 60; senior, 70.

Each column's total: bus, 50; car, 55; walk, 25.

And everyone: 130.

3 Expected counts

If there is no link, every row has the same share of each column as everyone does.

The column total over the grand total is that share.

Times the row total: the row total times the column total, over the grand total.

E = row total × column totaltotal

Junior, bus: 60 times 50, over 130, is about 23.0769.

junior, bus: 60 × 50 ÷ 130 ≈ 23.0769

Junior, car: 60 times 55, over 130, is about 25.3846.

junior, car: 60 × 55 ÷ 130 ≈ 25.3846

Junior, walk: 60 times 25, over 130, is about 11.5385.

junior, walk: 60 × 25 ÷ 130 ≈ 11.5385

Senior, bus: 70 times 50, over 130, is about 26.9231.

senior, bus: 70 × 50 ÷ 130 ≈ 26.9231

Senior, car: 70 times 55, over 130, is about 29.6154.

senior, car: 70 × 55 ÷ 130 ≈ 29.6154

Senior, walk: 70 times 25, over 130, is about 13.4615.

senior, walk: 70 × 25 ÷ 130 ≈ 13.4615

4 Each part

Chi-square adds up, for each cell, the observed minus the expected, squared, over the expected.

Squared, so misses up and down do not cancel.

Over the expected, so a miss counts more when we expected only a few.

χ2 = add up all (O − E)2E

A table: each cell, what we saw, O, and what we expected, E.

30 minus 23.0769 is 6.9231.

Squared, 47.9293.

Over 23.0769: 2.0769.

20 minus 25.3846 is −5.3846.

Squared, 28.9939.

Over 25.3846: 1.1422.

10 minus 11.5385 is −1.5385.

Squared, 2.367.

Over 11.5385: 0.2051.

20 minus 26.9231 is −6.9231.

Squared, 47.9293.

Over 26.9231: 1.7802.

35 minus 29.6154 is 5.3846.

Squared, 28.9939.

Over 29.6154: 0.979.

15 minus 13.4615 is 1.5385.

Squared, 2.367.

Over 13.4615: 0.1758.

5 Add them

2.0769 plus 1.1422 plus 0.2051 plus 1.7802 plus 0.979 plus 0.1758 is 6.3592.

χ2 = 2.0769 + 1.1422 + 0.2051 + 1.7802 + 0.979 + 0.1758 = 6.3592

6 The cut-off

df is rows minus 1, times columns minus 1: with the totals known, only that many cells can be filled freely.

1 times 2 is 2.

df = (rows − 1)(columns − 1) = (2 − 1)(3 − 1) = 2

Careful!

Not the number of cells minus 1.

Rows minus 1, times columns minus 1: 2.

The right way: df = (rows − 1)(columns − 1) = (2 − 1)(3 − 1) = 2.

Careful: not df = 5 ✗
right: df = (rows − 1)(columns − 1) = (2 − 1)(3 − 1) = 2 ✓

Chi-square is always a right-tail test: big means far from what we expected.

Row 2, column 0.05.

Row 2, column .05: the cut-off is 5.991.

7 Decide

The chi-square curve for df 2.

Past the cut-off, 5.991, is the reject part.

6.3592 is past the cut-off.

So we reject H zero.

χ2 = 6.3592 > 5.991 → reject H0

8 Say it in words

At the 5% level, there is enough evidence that

In words: at the 5% level, there is enough evidence that the group and the answer are linked.

the group and the answer are linked.

9 Check

Let's check: the expected counts give the same row totals.

Junior: 23.0769 plus 25.3846 plus 11.5385 is 60.

junior: E 23.0769 + 25.3846 + 11.5385 = 60 = 60

Senior: 26.9231 plus 29.6154 plus 13.4615 is 70.

So it is right!

senior: E 26.9231 + 29.6154 + 13.4615 = 70 = 70

10 Pick the choice

Our answer is reject H₀.

That is choice B.

B) Reject H0

11 Why not the others

A is Do not reject H0.

Wrong: χ² = 6.36 is more than 5.991.

A) Do not reject H0 ✗ χ² = 6.36 is more than 5.991

C is Accept H0.

Wrong: a test never shows H0 is true.

C) Accept H0 ✗ a test never shows H0 is true

D is Accept Ha because more seniors drive.

Wrong: the test decides.

D) Accept Ha because more seniors drive ✗ the test decides

Let's look back.

First: write the hypotheses.

Then: totals.

Then: expected counts.

Then: each part.

Then: add them.

Then: the cut-off.

Then: decide.

Then: say it in words.

Then: check.

Then: pick the choice.

Last: why not the others.

Answer
χ2 = 6.3592 > 5.991 → reject H0

Your turn

Try this one yourself, then check your answer:

junior: 20 bus, 31 car, 10 walk; senior: 35 bus, 20 car, 15 walk; α = 0.05
Show the answer
reject H0

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