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Limit of the sequence a_n = (5n^2 + n)/(3 - 2n^2)

Step by step, with the reason for every step · Limits of sequences · Calculus 2

Step by step

The question

Question: find the limit of the sequence a n = (5n² + n) over (−2n² + 3), as n grows.

an = 5n2 + n−2n2 + 3

1 The first terms

Work out a few terms: n = 1, 2, 3, then 10 and 100.

Put each n in.

Look at the terms.

They get close to −5/2.

They get close to −5 over 2

2 Divide by the highest power

Divide every term, top and bottom, by n to the 2, the highest power at the bottom.

The value does not change.

an = 5 + 1n−2 + 3n2

As n grows, 1/n gets as small as we like: it goes to 0.

So does any number over a power of n.

1n → 0

3 The limit

Every part with n at the bottom goes to 0.

as n → ∞ = 5 + 0−2 + 0

What is left: −5/2.

= −52

4 Decide

The terms settle on one number: the sequence converges to −5/2.

= converges to −52

Careful!

Top and bottom both grow, but that does not make the limit 1.

Divide by the highest power and see what is left.

Careful: not ∞∞ = 1 ✗

5 Check

Let's check with a calculator: term number 1000 is about −2.5005.

Close to −5/2.

Right!

n = 1000: an ≈ −2.5005

Let's look back.

First: the first terms.

Then: divide by the highest power.

Then: the limit.

Then: decide.

Last: check.

Answer
= converges to −52

Your turn

Try this one yourself, then check:

an = 2n2 + n−2n2 + 3
Show the answer
converges to −1

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