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Limit of the sequence a_n = (6n + 1)/(3n^2 + 2)

Step by step, with the reason for every step · Limits of sequences · Calculus 2

Step by step

The question

Question: find the limit of the sequence a n = (6n + 1)/(3n² + 2), as n grows.

an = 6n + 13n2 + 2

1 The first terms

Work out a few terms: n = 1, 2, 3, then 10 and 100.

Put each n in.

Look at the terms.

They get close to 0.

They get close to 0

2 Divide by the highest power

Divide every term, top and bottom, by n to the 2, the highest power at the bottom.

The value does not change.

an = 6n + 1n23 + 2n2

As n grows, 1/n gets as small as we like: it goes to 0.

So does any number over a power of n.

1n → 0

3 The limit

Every part with n at the bottom goes to 0.

as n → ∞ = 0 + 03 + 0

What is left: 0.

= 0

4 Decide

The terms settle on one number: the sequence converges to 0.

= converges to 0

Careful!

Converges means the terms settle on one number.

Careful: a limit is one number the terms settle on

5 Check

Let's check with a calculator: term number 1000 is about 0.002.

Close to 0.

Right!

n = 1000: an ≈ 0.002

Let's look back.

First: the first terms.

Then: divide by the highest power.

Then: the limit.

Then: decide.

Last: check.

Answer
= converges to 0

Your turn

Try this one yourself, then check:

an = n + 43n2 + 4
Show the answer
converges to 0

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