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Line through (0, 5) with slope 3

Step by step, with the reason for every step · Point-slope form · Algebra 1

Step by step

The question

Question: write the line through (0, 5) with slope 3 in point-slope form.

(0, 5) and m = 3

1 Rise = m × run

We call the slope m.

m = rise over run.

So the rise is m times the run.

rise = m × run

Like 8/2 is 4, so 8 is 4 times 2.

82 = 4 → 8 = 4 × 2

Take any point (x, y) on the line.

We go from (0, 5) to (x, y).

The rise is y − 5: the change in y.

The run is x − 0: the change in x.

rise = y − 5
run = x − 0

Put them in: rise = m × run becomes y − 5 = 3(x − 0).

y − 5 = 3(x − 0)

Taking away 0 changes nothing.

− 0: nothing changes

So it becomes y − 5 = 3x.

y − 5 = 3x

This is called point-slope form.

It is made from a point and the slope.

y − y1 = m(x − x1)

2 Write as y = mx + b

We want y by itself.

The − 5 is in the way.

To remove − 5, we add 5.

We do it on both sides, so they stay equal.

y − 5 + 5 = 3x + 5

− 5 and + 5 make zero.

Cross them out.

So y = 3x + 5.

y = 3x + 5

3 Check

Let's check: put x = 0 into y = 3x + 5.

We get 5, the y of (0, 5).

y = 3(0) + 5 = 0 + 5 = 5

And the number in front of x is 3: the slope.

Right!

m = 3

Let's look back.

First: rise = m × run.

Then: write as y = mx + b.

Last: check.

Answer
y − 5 = 3x

Your turn

Try this one yourself, then check:

Write the line through (0, 3) and m = 3
Show the answer
y − 3 = 3x, y = 3x + 3

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