Steply

Line through (4, 0) with slope 1/2

Step by step, with the reason for every step · Point-slope form · Algebra 1

Step by step

The question

Question: write the line through (4, 0) with slope 1/2 in point-slope form.

(4, 0) and m = 12

1 Rise = m × run

We call the slope m.

m = rise over run.

So the rise is m times the run.

rise = m × run

Like 8/2 is 4, so 8 is 4 times 2.

82 = 4 → 8 = 4 × 2

Take any point (x, y) on the line.

We go from (4, 0) to (x, y).

The rise is y − 0: the change in y.

The run is x − 4: the change in x.

rise = y − 0
run = x − 4

Put them in: rise = m × run becomes y − 0 = (1/2) times (x − 4).

y − 0 = 12(x − 4)

Taking away 0 changes nothing.

− 0: nothing changes

So it becomes y = (1/2) times (x − 4).

y = 12(x − 4)

This is called point-slope form.

It is made from a point and the slope.

y − y1 = m(x − x1)

2 Write as y = mx + b

The 1/2 in front of the bracket multiplies every part inside.

So we write 1/2 times each part.

y = 12 × x + 12 × (−4)

Work out each multiplication.

So y = (1/2)x − 2.

y is already by itself.

y = 12x − 2

3 Check

Let's check: put x = 4 into y = (1/2)x − 2.

We get 0, the y of (4, 0).

y = 12(4) − 2 = 2 − 2 = 0

And the number in front of x is 1/2: the slope.

Right!

m = 12

Let's look back.

First: rise = m × run.

Then: write as y = mx + b.

Last: check.

Answer
y = 12(x − 4)

Your turn

Try this one yourself, then check:

(2, 0) and m = 32
Show the answer
y = 32(x − 2), y = 32x − 3

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