Steply

Max and min of f(x, y) = 2x - y on x^2 + y^2 = 20

Step by step, with the reason for every step · Lagrange multipliers · Calculus 3

Step by step

The question

Question: find the maximum and minimum of f(x, y) = 2x − y with x² + y² = 20.

f(x, y) = 2x − y, x2 + y2 = 20

1 Set up the equations

At the best point, the level curve of f just touches the curve.

So the two gradients point the same way.

The rule: ∇f = λ∇g.

λ is the Greek letter lambda.

It is just a number.

∇f = λ ∇g

The curve is g = 20, with g(x, y) = x² + y².

g(x, y) = x2 + y2

The x parts: f_x = λ g_x.

f_x is 2, g_x is 2x.

① 2 = λ × 2x

The y parts: f_y = λ g_y.

f_y is −1, g_y is 2y.

② −1 = λ × 2y

And ③: stay on the curve.

③ x2 + y2 = 20

Careful!

The curve's own equation is part of the system.

Without it, we cannot find x and y.

Careful: three equations: never forget ③

2 Solve the equations

From ①: 2 = λ × 2x, so λ is 2/2x.

λ = 22x

From ②: λ is −1/2y.

λ = −12y

Both are λ, so they are equal.

22x = −12y

Cross-multiply and tidy up: y = −1/2x.

y = −12x

Put it into ③.

x² + (−1/2x)² = 20

Add the x² terms and divide: x² = 16.

x² = 16

Two numbers: x = 4 or −4.

Then y follows: two points.

x = 4 or −4

3 Compare the values

At (4, −2), f is 10.

f(4, −2) = 10

At (−4, 2), f is −10.

f(−4, 2) = −10

The bigger value is the maximum, the smaller one the minimum.

= max 10 at (4, −2), min −10 at (−4, 2)

4 Check

Let's check on the xy grid.

The orange circle is the curve ③.

The blue lines are where f is 10 and −10.

Each just touches the circle.

Another point on the circle gives −4.47: between the two.

Right!

f(0, 4.47) = −4.47

Let's look back.

First: set up the equations.

Then: solve the equations.

Then: compare the values.

Last: check.

Answer
= max 10 at (4, −2), min −10 at (−4, 2)

Your turn

Try this one yourself, then check:

Find the maximum and minimum of f(x, y) = 4x − 2y, x2 + y2 = 20
Show the answer
max 20 at (4, −2), min −20 at (−4, 2)

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