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Minimize C = 2x + 3y: x ≥ 0, y ≥ 0, x + y ≥ 4, x + 3y ≥ 6

Step by step, with the reason for every step · Linear programming · Algebra 1

Step by step

The question

Question: minimize C = 2x + 3y, when x ≥ 0, y ≥ 0, x + y ≥ 4, x + 3y ≥ 6.

minimize C = 2x + 3y

Minimize means: make C as small as it can be.

x and y must follow every rule.

= x ≥ 0, y ≥ 0, x + y ≥ 4, x + 3y ≥ 6

1 Draw the lines

A grid for x and y.

The edge of x + y ≥ 4 is the line x + y = 4.

It crosses the axes at (4, 0) and (0, 4).

Solid: "or equal to".

The edge of x + 3y ≥ 6 is the line x + 3y = 6.

It crosses the axes at (6, 0) and (0, 2).

Solid: "or equal to".

2 Shade the region

x ≥ 0 and y ≥ 0: right of the y-axis, above the x-axis.

"Greater than or equal": the side away from (0, 0).

The shaded part fits every rule.

3 Find the corners

The corners are where two edges of the region meet.

Where x + y = 4 meets x + 3y = 6: we solve the two together, as in the systems lesson.

x = 3, y = 1.

x + y = 4 and x + 3y = 6: x = 3, y = 1

4 Test each corner

At (0, 4): C = 12.

(0, 4): C = 2(0) + 3(4) = 12

At (6, 0): C = 12.

(6, 0): C = 2(6) + 3(0) = 12

At (3, 1): C = 9.

(3, 1): C = 2(3) + 3(1) = 9

Careful!

The smallest value is always at a corner of the shaded region.

So we only test the corners.

Careful: the best point is always a corner of the region

5 Pick the best

The smallest is 9, at x = 3, y = 1.

minimum C = 9 at (3, 1)

6 Check

Let's check with a point inside the region, (4, 2): C is 14.

That is more than 9.

So the corner is the best!

inside: (4, 2): C = 14 > 9

Let's look back.

First: draw the lines.

Then: shade the region.

Then: find the corners.

Then: test each corner.

Then: pick the best.

Last: check.

Answer
minimum C = 9 at (3, 1)

Your turn

Try this one yourself, then check:

minimize C = 2x + 5y
Show the answer
minimum C = 11 at (3, 1)

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