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Minimize C = 3x + 2y: x ≥ 0, y ≥ 0, x + y ≥ 5, 2x + y ≥ 6

Step by step, with the reason for every step · Linear programming · Algebra 1

Step by step

The question

Question: minimize C = 3x + 2y, when x ≥ 0, y ≥ 0, x + y ≥ 5, 2x + y ≥ 6.

minimize C = 3x + 2y

Minimize means: make C as small as it can be.

x and y must follow every rule.

= x ≥ 0, y ≥ 0, x + y ≥ 5, 2x + y ≥ 6

1 Draw the lines

A grid for x and y.

The edge of x + y ≥ 5 is the line x + y = 5.

It crosses the axes at (5, 0) and (0, 5).

Solid: "or equal to".

The edge of 2x + y ≥ 6 is the line 2x + y = 6.

It crosses the axes at (3, 0) and (0, 6).

Solid: "or equal to".

2 Shade the region

x ≥ 0 and y ≥ 0: right of the y-axis, above the x-axis.

"Greater than or equal": the side away from (0, 0).

The shaded part fits every rule.

3 Find the corners

The corners are where two edges of the region meet.

Where x + y = 5 meets 2x + y = 6: we solve the two together, as in the systems lesson.

x = 1, y = 4.

x + y = 5 and 2x + y = 6: x = 1, y = 4

4 Test each corner

At (0, 6): C = 12.

(0, 6): C = 3(0) + 2(6) = 12

At (5, 0): C = 15.

(5, 0): C = 3(5) + 2(0) = 15

At (1, 4): C = 11.

(1, 4): C = 3(1) + 2(4) = 11

Careful!

The smallest value is always at a corner of the shaded region.

So we only test the corners.

Careful: the best point is always a corner of the region

5 Pick the best

The smallest is 11, at x = 1, y = 4.

minimum C = 11 at (1, 4)

6 Check

Let's check with a point inside the region, (2, 5): C is 16.

That is more than 11.

So the corner is the best!

inside: (2, 5): C = 16 > 11

Let's look back.

First: draw the lines.

Then: shade the region.

Then: find the corners.

Then: test each corner.

Then: pick the best.

Last: check.

Answer
minimum C = 11 at (1, 4)

Your turn

Try this one yourself, then check:

minimize C = 4x + 3y
Show the answer
minimum C = 16 at (1, 4)

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