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Normal mean 12, sd 1.5: value with 60% below it

Step by step, with the reason for every step · Normal cut-offs · University Statistics

Step by step

The question

Question: X is normal, with mean 12 and SD 1.5: which value has 60% below it?

μ = 12, σ = 1.5: x with 60% below it?

A value with 60 percent below it is also called the 60th percentile.

60% below it = the 60th percentile

1 Shade the area

The bell, with the mean 12 in the middle.

x is the cut-off we want.

60 percent is below x: we shade it, on the left of x.

2 Area to the left

The z-table works with the area to the left of z.

z-table: area to the left of z

60 percent is 0.6.

It is already on the left.

area to the left = 0.6

Careful!

More than half the bell is on the left.

So x is above the mean, and z is positive.

Careful: more than half on the left: z is positive

3 Find it inside the table

Now we look for 0.6000 inside the table.

The closest number is 0.5987: row 0.2, column .05.

So z is about 0.25.

4 Back to x

Start at the mean, then go z SDs: x is the mean plus z times the SD.

x = μ + z × σ

0.25 times 1.5 is 0.375.

12 plus 0.375 is 12.375.

x = 12 + 0.25 × 1.5 = 12 + 0.375 = 12.375

5 Check

Let's check: the z of 12.375 is 12.375 minus 12, over 1.5.

That is 0.25.

z = 12.375 − 121.5 = 0.25

The table at 0.25 gives 0.5987: about 0.6 to the left.

So it is right!

table at z = 0.25: 0.5987 ≈ 0.6

Let's look back.

First: shade the area.

Then: area to the left.

Then: find it inside the table.

Then: back to x.

Last: check.

Answer
x = 12 + 0.25 × 1.5 = 12 + 0.375 = 12.375

Your turn

Try this one yourself, then check:

μ = 22, σ = 1.5: x with 60% below it?
Show the answer
x = 22.375

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