Steply

Partial derivatives of f(x, y) = x^4 - 3xy^2 + 6y

Step by step, with the reason for every step · Partial derivatives · Calculus 3

Step by step

The question

Question: find the partial derivatives of f(x, y) = x⁴ − 3xy² + 6y.

f(x, y) = x4 − 3xy2 + 6y

1 Partial by x

The partial derivative ∂f/∂x is the slope when only x changes.

∂f/∂x: only x changes

For ∂f/∂x, only x changes.

y stays fixed: it acts like a plain number.

It is purple now.

f(x, y) = x4 − 3xy2 + 6y

Term by term.

x⁴: the power 4 comes down.

The power goes down by 1.

So 4x³.

In 3xy², 3y² is fixed and waits in front.

x gives 1.

So 3y².

6y has no x: it is a fixed number, so it gives 0.

∂f∂x = 4x3 − 3y2 + 0

Drop the zeros: ∂f/∂x = 4x³ − 3y².

∂f∂x = 4x3 − 3y2

Careful!

A fixed letter is not 0!

In x²y, y stays in front.

Only a term with no x at all gives 0.

Careful: fixed y is not 0

2 Partial by y

For ∂f/∂y, only y changes.

x stays fixed: it acts like a plain number.

It is purple now.

f(x, y) = x4 − 3xy2 + 6y

Term by term.

x⁴ has no y: it is a fixed number, so it gives 0.

In 3xy², 3x is fixed and waits in front.

y² gives 2y.

So 6xy.

6y gives 6.

∂f∂y = 0 − 6xy + 6

Drop the zeros: ∂f/∂y = −6xy + 6.

∂f∂y = −6xy + 6

3 Check

Let's check.

Here is the surface z = f(x, y) near (1, 2).

On the orange curve only x changes.

∂f/∂x is its slope.

On the purple curve only y changes.

∂f/∂y is its slope.

The slope between two very close points.

Move x by 0.001: the change in f, over 0.001, is about −7.99.

f(1.001, 2) − f(1, 2)0.001 = 0.992006 − 10.001 ≈ −7.994

And ∂f/∂x at that point is −8.

Almost the same.

Right!

∂f∂x at (1, 2) = −8

Now move y by 0.001: the change in f, over 0.001, is about −6.

f(1, 2.001) − f(1, 2)0.001 = 0.993997 − 10.001 ≈ −6.003

And ∂f/∂y at that point is −6.

Almost the same.

Right!

∂f∂y at (1, 2) = −6

Let's look back.

First: partial by x.

Then: partial by y.

Last: check.

Answer
Careful: fixed y is not 0

Your turn

Try this one yourself, then check:

Find the partial derivatives of f(x, y) = 3x4 − 6xy2 + y
Show the answer
∂f∂x = 12x³ − 6y², ∂f∂y = −12xy + 1

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