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Prove if n is even, then 3n + 5 is odd

Step by step, with the reason for every step · Direct proof · Discrete Math

Step by step

The question

Question: prove that if n is even, then 3n + 5 is odd.

1 Write it with letters

n is even, so n = 2a, where a is a whole number.

n = 2a

That is what even means.

even = 2 × a whole number

Careful!

An example shows one number.

The letters show every number at once.

Careful: one example is not a proof

2 Put them in

Now put them in: 3n + 5 becomes 3(2a) + 5.

3n + 5 = 3(2a) + 5

3 Work it out

Open the brackets: 6a + 5.

= 6a + 5

4 Show the form

We take out 2 from all but the 1: 2(3a + 2) + 1.

= 2(3a + 2) + 1

3a + 2 is a whole number, because whole numbers added and multiplied stay whole.

3a + 2 is a whole number

2 times a whole number, plus 1: that is the form of an odd number.

So 3n + 5 is odd.

So 3n + 5 is odd. ∎

The square at the end means: the proof is done.

5 Check

An example: n = 2.

It gives 11.

n = 2: 3 × 2 + 5 = 11

11 is 2 times 5, plus 1: odd, as the proof says.

Right!

11 = 2 × 5 + 1

Let's look back.

First: write it with letters.

Then: put them in.

Then: work it out.

Then: show the form.

Last: check.

Answer
3a + 2 is a whole number

Your turn

Try this one yourself, then check:

Show the answer
4n + 5 = 2(4a + 4) + 1

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