Steply

Prove the sum of two odd numbers is even

Step by step, with the reason for every step · Direct proof · Discrete Math

Step by step

The question

Question: prove that the sum of two odd numbers is even.

1 Write it with letters

x is odd, so x = 2a + 1, where a is a whole number.

x = 2a + 1

That is what odd means.

odd = 2 × a whole number + 1

y is odd, so y = 2b + 1, where b is a whole number.

A new letter, b: y can be a different number from x.

y = 2b + 1

Careful!

The same letter would make x and y the same number.

Two numbers need two letters.

Careful: not x = 2a + 1, y = 2a + 1 ✗

2 Put them in

Now put them in: x + y becomes (2a + 1) + (2b + 1).

x + y = (2a + 1) + (2b + 1)

3 Work it out

Open the brackets: 2a + 1 + 2b + 1.

= 2a + 1 + 2b + 1

Like terms together: 2a + 2b + 2.

= 2a + 2b + 2

4 Show the form

Every term has a 2 in it.

We take out 2: 2(a + b + 1).

= 2(a + b + 1)

a + b + 1 is a whole number, because whole numbers added and multiplied stay whole.

a + b + 1 is a whole number

2 times a whole number: so x + y is even.

So x + y is even. ∎

The square at the end means: the proof is done.

5 Check

An example: x = 3 and y = 5.

It gives 8.

x = 3, y = 5: 3 + 5 = 8

8 is 2 times 4: even, as the proof says.

Right!

8 = 2 × 4

Let's look back.

First: write it with letters.

Then: put them in.

Then: work it out.

Then: show the form.

Last: check.

Answer
a + b + 1 is a whole number

Your turn

Try this one yourself, then check:

Show the answer
xy = 2 × 2ab

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