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Remainder when x^3 - 2x^2 + 4 is divided by x - 3

Step by step, with the reason for every step · Remainder and factor theorem · Algebra 2

Step by step

The question

Question: find the remainder when x³ − 2x² + 4 is divided by (x − 3).

x3 − 2x2 + 4x − 3

The remainder theorem: when we divide by x minus a number, the remainder is what f gives for that number.

We don't need to divide.

divide by x − c → remainder = f(c)

1 Call it f(x)

Let's call the polynomial f(x).

f(x) = x3 − 2x2 + 4

2 Make x − 3 zero

Which x makes x − 3 zero?

x − 3 = 0

3 take away 3 is 0.

So x = 3.

x = 3

Careful!

Many people put in −3, the number they see.

But x − 3 is 0 when x is 3.

Careful: not f(−3) ✗

3 Work out f(3)

Put 3 in place of every x.

We write it in brackets.

f(3) = 33 − 2(3)2 + 4

Work out each part: the powers first, then the times.

= 27 − 18 + 4

Then add and take away from left to right.

f(3) = 13.

f(3) = 13

4 Read the remainder

So the remainder is 13.

remainder = 13

5 Check

Let's check with synthetic division, from the division lesson.

We use 3 again.

The last number in the table is the remainder: 13.

The same as f(3)!

Last number: 13 = f(3)

Let's look back.

First: call it f(x).

Then: make x − 3 zero.

Then: work out f(3).

Then: read the remainder.

Last: check.

Answer
remainder = 13

Your turn

Try this one yourself, then check:

remainder of x3 + x2 + 3x − 2
Show the answer
remainder = 15

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