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Remainder when x^3 - 4x + 1 is divided by x + 2

Step by step, with the reason for every step · Remainder and factor theorem · Algebra 2

Step by step

The question

Question: find the remainder when x³ − 4x + 1 is divided by (x + 2).

x3 − 4x + 1x + 2

The remainder theorem: when we divide by x minus a number, the remainder is what f gives for that number.

We don't need to divide.

divide by x − c → remainder = f(c)

1 Call it f(x)

Let's call the polynomial f(x).

f(x) = x3 − 4x + 1

2 Make x + 2 zero

Which x makes x + 2 zero?

x + 2 = 0

x + 2 is the same as x minus −2.

So c is −2.

x + 2 = x − (−2)

−2 plus 2 is 0.

So x = −2.

x = −2

Careful!

Many people put in 2, the number they see.

But x + 2 is 0 when x is −2.

Careful: not f(2) ✗

3 Work out f(−2)

Put −2 in place of every x.

We write it in brackets.

f(−2) = (−2)3 − 4(−2) + 1

Work out each part: the powers first, then the times.

= −8 + 8 + 1

Then add and take away from left to right.

f(−2) = 1.

f(−2) = 1

4 Read the remainder

So the remainder is 1.

remainder = 1

5 Check

Let's check with synthetic division, from the division lesson.

We use −2 again.

The last number in the table is the remainder: 1.

The same as f(−2)!

Last number: 1 = f(−2)

Let's look back.

First: call it f(x).

Then: make x + 2 zero.

Then: work out f(−2).

Then: read the remainder.

Last: check.

Answer
remainder = 1

Your turn

Try this one yourself, then check:

remainder of x3 − 4x − 1x + 1
Show the answer
remainder = 2

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