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Right angle at A, AD ⊥ BC, AD = 6, BD = 4, find DC

Step by step, with the reason for every step · Right triangle with its height to the hypotenuse · Geometry

Step by step

The question

Question: triangle A B C has a right angle at A, and A D is at 90° to B C, with AD = 6, BD = 4: find DC.

1 Find the similar triangles

The height A D cuts the big triangle into two small ones.

All three triangles have a right angle, and they share their other angles.

So they are similar: the same shape.

2 Write the rule

Triangles D B A and D A C: B D over A D equals A D over D C.

Cross-multiplied, that gives the rule: AD squared is BD times DC.

AD2 = BD × DC

Careful!

It is BD times DC, not plus.

Careful: not AD² = BD + DC ✗

3 Put the numbers in

Put the numbers in.

We call DC x.

62 = 4 × x

6 squared is 36.

36 = 4 × x

4 Remove the 4

To remove times 4, we divide both sides by 4: 9.

x = 364 = 9

5 Check

Let's check with Pythagoras in the small triangle A B D: A D squared plus B D squared is 52 the same as A B squared.

So it fits!

triangle ABD: AD² + BD² = 36 + 16 = 52 = AB² = 52

Let's look back.

First: find the similar triangles.

Then: write the rule.

Then: put the numbers in.

Then: remove the 4.

Last: check.

Answer
x = 364 = 9

Your turn

Try this one yourself, then check:

Find DC.
Show the answer
DC = 16

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