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Right angle at A, AD ⊥ BC, BD = 4, BC = 9, find AB

Step by step, with the reason for every step · Right triangle with its height to the hypotenuse · Geometry

Step by step

The question

Question: triangle A B C has a right angle at A, and A D is at 90° to B C, with BD = 4, BC = 9: find AB.

1 Find the similar triangles

The height A D cuts the big triangle into two small ones.

All three triangles have a right angle, and they share their other angles.

So they are similar: the same shape.

2 Write the rule

Triangles D B A and A B C: B D over A B equals A B over B C.

Cross-multiplied, that gives the rule: AB squared is BD times BC.

AB2 = BD × BC

Careful!

It is BD times BC, not plus.

Careful: not AB² = BD + BC ✗

3 Put the numbers in

Put the numbers in.

We call AB x.

x2 = 4 × 9

4 times 9 is 36.

x2 = 36

4 Take the square root

x is the square root of 36.

A length is positive: 6.

x = √36 = 6

5 Check

Let's check with Pythagoras in the small triangle A B D: A D squared plus B D squared is 36 the same as A B squared.

So it fits!

triangle ABD: AD² + BD² = 20 + 16 = 36 = AB² = 36

Let's look back.

First: find the similar triangles.

Then: write the rule.

Then: put the numbers in.

Then: take the square root.

Last: check.

Answer
x = √36 = 6

Your turn

Try this one yourself, then check:

Find AB.
Show the answer
AB = 6

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